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Sergio039 [100]
3 years ago
14

How many moles of hydrogen gas are produced when 0.066 mole of sodium is completely reacted?

Chemistry
2 answers:
velikii [3]3 years ago
8 0

Answer : The number of moles of hydrogen gas is, 0.033 mole

Explanation : Given,

Moles of sodium = 0.066 mole

The balanced chemical reaction will be,

2Na(s)+2H_2O(l)\rightarrow 2NaOH(aq)+H_2(g)

From the balanced chemical reaction, we conclude that 2 moles of sodium  react with 2 moles of water to give 2 moles of sodium hydroxide and 1 mole of hydrogen has as a product.

As, 2 moles of sodium react to give 1 mole of hydrogen gas

So, 0.066 mole of sodium react to give \frac{1}{2}\times 0.066=0.033 moles of hydrogen gas

Therefore, the number of moles of hydrogen gas is, 0.033 mole

SVEN [57.7K]3 years ago
6 0
Base on my research the complete reaction of hydrogen and sodium are form by this equation  2Na + 2H2O = 2NaOH +H2 If we base from this equation it shows you already the ratio of the moles of the product and reactants taking part in the reaction

1 mole of Na r/w 1 mole of water to produce .5 mole of Hydrogen 

Therefore, .066 mole of Na produces .033 moles of H2
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Use the combined gas law (convert temperatures to Kelvin first).

P1V1/T1 = P2V2/T2
P1 = 0.5 atm
V1 = 143 mL
T1 = 35.0°C = 308 K
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V2 = ?
T2 = 0°C = 273 K

Solve the equation for V2 and you get:
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Answer:

0.89

Explanation:

You are mixing an acid and a base, so there will be a neutralization reaction.

One of the reactants will be in excess, so we must determine its concentration and then calculate the pH.

<em>Moles of NaOH </em>

Moles of NaOH = 25 × 0.173

Moles of NaOH = 4.32 mmol

===============

<em>Moles of HCl </em>

Moles of HCl = 35 × 0.342

Moles of HCl = 12.0 mmol

===============

<em>Amount of excess reactant </em>

              NaOH + HCl ⟶ NaCl +H₂O

<em>n</em>/mmol:   4.32      12.0

The 4.32 mmol of NaOH reacts completely with 4.32 mmol of HCl.

Excess HCl = 12.0 – 4.32

Excess HCl = 7.6 mmol

===============

<em>Concentration of the excess HCl </em>

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Total volume = 60 mL

<em>c </em>= millimoles HCl/millilitres HCl

<em>c</em> = 7.6/60

<em>c</em> = 0.13 mol/L

===============

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The HCl dissociates completely to hydronium ions, so

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pH = -log[H₃O⁺]

pH = -log0.13

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Answer:

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