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Sidana [21]
2 years ago
14

Can someone help me with this? Last one is -1/4 btw

Mathematics
1 answer:
Leya [2.2K]2 years ago
5 0
2 because rise/run so 8/4 which=2
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In parallelogram ABCD, AB = 16 cm, DA = 3<img src="https://tex.z-dn.net/?f=%5Csqrt%7B2%7D" id="TexFormula1" title="\sqrt{2}" alt
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Answer:

length of segment YZ is 8 cm

Step-by-step explanation:

given data

AB = 16 cm

DA = 3\sqrt{2} cm

AB and DA form interior angle  =  45-degre

WX ≠ YZ

WX = 16 cm

to find out

length of segment YZ

solution

area of △ABD is  the same as the area of △BCD

and

area of △ABD is express as

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area of △ABD = 16 × 3√2 × sin(45) ÷ 2

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and

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area of the parallelogram = 24 × 2

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so

now we will consider here YZ = x

and Since ZY XW is isosceles trapezoid

so here we can say that

WM = ZM = (16 - x)  ÷ 2   .......................2

so area of  trapezoid will be

area of  trapezoid = \frac{ZY + WX }{2}  \times ZM         .......................3

area of  trapezoid = \frac{x+16}{2} \times \frac{16 - x}{2}    

48 = \frac{x+16}{2} \times \frac{16 - x}{2}  

solve it we get

x = 8

so length of segment YZ is 8 cm

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