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JulijaS [17]
4 years ago
10

All objects moving in a circle experience a centripetal force. The form of centripetal force depends on the object in circular m

otion and the force causing the circular movement. Which of the following describes the correct centripetal force acting on an object moving in a circle?
The force of air resistance as a rollercoaster performs a loop on a track.
The force of friction as a car drives around a corner at constant speed.
The force of gravity as a ball on a string is spun horizontally in a circle.
The force of inertia as a person spins on a ride at an amusement park.
Physics
1 answer:
lana [24]4 years ago
3 0

Answer:

The force of friction as a car drives around a corner at constant speed

Explanation:

The centripetal force is an external resultant force that is directed towards the center of circle which object is rotated and perpendicular to the direction of velocity.

The force of friction is always towards the center of the arc with car is turned and it is always perpendicular to the direction of motion.

We also can derive equation,

v^{2} = μrg by considering friction as the centripetal force.

Check the attachment for workings.

Download pdf
You might be interested in
An electron moves in the plane of this screen toward the top of the screen. A magnetic field is also in the plane of the screen
Ad libitum [116K]

Answer: the direction of the magnetic force on the electron will be moving out of the screen, perpendicular to the magnetic field.

Explanation:

The magnetic force F on a moving electron at right angle to a magnetic field is given by the formula:

F = BqVSinØ

If an electron moves in the plane of this screen toward the top of the screen. A magnetic field is also in the plane of the screen and directed toward the right. Then, the direction of the magnetic force on the electron will be perpendicular to the magnetic field

According to the Fleming's left - hand rule, the direction of the magnetic force on the electron will be moving out of the plane of the screen.

6 0
4 years ago
the passengers in a roller coaster feel 50 heavier than their true weight as the car goes through a dip with a 30m radius of cur
NeTakaya

Answer:

v = 12.12 m/s

Explanation:

Given that,

Radius of the curvature, r = 30 m

To find,

The car's speed at the bottom of the dip.

Solution,

Let mg is the true weight of the passenger. When it is moving in the circular path, the centripetal force act on it. It is given by :

F=\dfrac{mv^2}{r}

The normal reaction of the passenger is given by :

N=mg-50\%mg

N = 1.5 mg

Let v is the car's speed at the bottom of the dip. It can be calculated as:

1.5\ mg-mg=\dfrac{mv^2}{r}

v=\sqrt{0.5gr}

v=\sqrt{0.5\times 9.8\times 30}

v = 12.12 m/s

So, the speed of the car at the bottom of the dip is 12.12 m/s. Hence, this is the required solution.

7 0
3 years ago
Can anyone plz answer this?
Scrat [10]

Answer:

I would say C

Explanation:

A is a steep or about 45° angle while B appears to be a straight down angle of 0°. So if you take that into account, if you are subtracting A and B, it would be around in between. It will probably not be backwards because neither is facing to the left except the answer choices so B is wrong (the answer B).

R is even steeper than before, and if you are subtracting, it would probably be C.

7 0
3 years ago
Which of the following animals have adapted to live in the arctic tundra? (Select all that apply.)
sashaice [31]

Answer:

no way I had that question too :-O anyways here's the answer

Explanation:

willow ptarmigan and Walia ibex

5 0
3 years ago
When an object with a height of 0.10 meter is placed at a distance of 0.20 meter from a convex
seraphim [82]

Answer:

h = 0.1 m = 10 cm

u = 0.2 m = 20 cm

v = 0.06 m = 6 cm

m = h'/h = v/u

h'/10 = 6/20

h' = 60/20 = 3 cm

Therefore image height = 3 cm(0.03 m)

Hope this helps!

8 0
3 years ago
Read 2 more answers
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