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JulijaS [17]
4 years ago
10

All objects moving in a circle experience a centripetal force. The form of centripetal force depends on the object in circular m

otion and the force causing the circular movement. Which of the following describes the correct centripetal force acting on an object moving in a circle?
The force of air resistance as a rollercoaster performs a loop on a track.
The force of friction as a car drives around a corner at constant speed.
The force of gravity as a ball on a string is spun horizontally in a circle.
The force of inertia as a person spins on a ride at an amusement park.
Physics
1 answer:
lana [24]4 years ago
3 0

Answer:

The force of friction as a car drives around a corner at constant speed

Explanation:

The centripetal force is an external resultant force that is directed towards the center of circle which object is rotated and perpendicular to the direction of velocity.

The force of friction is always towards the center of the arc with car is turned and it is always perpendicular to the direction of motion.

We also can derive equation,

v^{2} = μrg by considering friction as the centripetal force.

Check the attachment for workings.

Download pdf
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Answer:

0.661 m/s²

Explanation:

g = MG / r²

g = (1.31×10²² kg) (6.67×10⁻¹¹ m³/kg/s²) / (1.15×10⁶ m)²

g = 6.61×10⁻¹ m/s²

g = 0.661 m/s²

3 0
3 years ago
A speed skater moving across frictionless ice at 9.2 m/s hits a 5.0 m wide patch of rough ice. She slows steadily, then continue
enot [183]

Answer:

a = -5.10 m/s^2

her acceleration on the rough ice is -5.10 m/s^2

Explanation:

The distance travelled on the rough ice is equal to the width of the rough ice.

distance d = 5.0 m

Initial speed u = 9.2 m/s

Final speed v = 5.8 m/s

The time taken to move through the rough ice can be calculated using the equation of motion;

d = 0.5(u+v)t

time t = 2d/(u+v)

Substituting the given values;

t = 2(5)/(9.2+5.8)

t = 2/3 = 0.66667 second

The acceleration is the change in velocity per unit time;

acceleration a = ∆v/t

a = (v-u)/t

Substituting the values;

a = (5.8-9.2)/0.66667

a = -5.099974500127

a = -5.10 m/s^2

her acceleration on the rough ice is -5.10 m/s^2

7 0
3 years ago
Determine the mechanical energy of this object: a 2-kg pendulum has a speed of 1 m/s at a height of 1/2 meter.
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The answer is B 10.8 j 
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Answer:

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Explanation:

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F2 = G•2.2•4.66/3² (pointed left)

subtract the two to get zero

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3 years ago
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= (18 x 10^-6 /°C)(0.125 m)(100° C - 200 °C)

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= 1.25 m + (-0.00225 m)
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So your answer is B.
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