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Illusion [34]
3 years ago
12

Since the moon has less mass then the earth what happens to objects on the moon

Physics
1 answer:
marshall27 [118]3 years ago
4 0

A) They move slower


Gravity force is determined by mass and the size of the moon. Since the mass of the moon is significantly lower than the mass of Earth, it will pull objects slower. The only object that would fall faster on the moon than on earth is a sheet of paper since there is much, much less air resistance to affect its terminal velocity the way it does on the earth.

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The maximum distance which our normal eye can see distinctly is known as _______________
azamat

Answer:

Far point.

Explanation:

The maximum distance up to which the normal eye can see objects distinct and clear is called the far point of the eye. It is infinity for a normal eye.

7 0
2 years ago
What is the amount of electric current passing through the heating oil of a hot plate if 25 C of charge passes through it in 7 s
coldgirl [10]

Answer:

Current, I = 3.57A

Explanation:

A current of I amperes means that I Coulombs of charge flows through the conductor (heating coil) per second.

Therefore, in time t, the total charge (Q) passing through any point in which the current (C) flows will be given by the equation;

Q = It

Where; Q is the charge in coulombs; I is the current in amperes; t is the time in seconds.

From the question, we were given the following parameters;

Q = 25C, t= 7secs and I =?

From the equation, Q = It

We make current, I the subject of formula;

Thus, I = Q/t

Substituting into the equation;

I = 25/7

I = 3.57Amp.

3 0
3 years ago
An infinite sheet carries a uniform, positive charge per unit area. The electric field produced by the sheet is represented by p
nexus9112 [7]

Complete Question

An infinite sheet carries a uniform, positive charge per unit area. The electric field produced by the sheet is represented by parallel lines drawn with a density N lines per m2 that are perpendicular to and away from the sheet. The charge per unit area on the sheet is doubled. How should the density of the electric field lines be changed?

A It should stay the same

B  It should be quadrupled.

C It should be quintupled

D It should be doubled.

E It should be tripled

Answer:

Option D is the correct option

Explanation:

Generally electric field is mathematically represented as

        E =  \frac{\sigma}{\epsilon_o}

Where \sigma is the charge per unit area (Charge density )

From the question we are told that \sigma is doubled hence the

     E =  \frac{2 \sigma }{\epsilon_o}    

Looking the equation above we see that the value of the electric field will also double given that it is directly proportional to the charge density

8 0
3 years ago
A baseball is thrown at an angle of 20° relative to the ground at a speed of 25 m/s if the ball was caught 50 m from the thrower
scoray [572]

Answer:

2.1 s

Explanation:

The motion of the ball is a projectile motion. We know that the horizontal range of the ball is

d = 50 m

And that the initial speed of the ball is

u=25 m/s

at an angle of

\theta=20^{\circ}

So, the horizontal speed of the ball (which is constant during the entire motion) is

u_x = u cos \theta = 25 \cdot cos 20^{\circ} = 23.5 m/s

And since the horizontal range is 50 m, the time taken for the ball to cover this distance was

t=\frac{d}{u_x}=\frac{50}{23.5}=2.1 s

which is the time the ball spent in air.

8 0
3 years ago
A 100 kg box as showsn above is being pulled along the x axis by a student. the box slides across a rough surface, and its posit
Anit [1.1K]

Answer:

a) 2 m/s

b) i) K.E = 50 (1.5t^2 + 2) ^2\\

ii) F = 3tm

Explanation:

The function for distance is x = 0.5t ^3 + 2t

We know that:

Velocity = v= \frac{d}{dt} x

Acceleration = a= \frac{d}{dt}v

To find speed at time t = 0, we derivate the distance function:

x = 0.5 t^3 + 2t\\v= x' = 1.5t^2 + 2

Substitute t = 0 in velocity function:

v = 1.5t^2 + 2\\v(0) = 1.5 (0) + 2\\v(0) = 2

Velocity at t = 0 will be 2 m/s.

To find the function for Kinetic Energy of the box at any time, t.

Kinetic \ Energy = \frac{1}{2} mv^2\\\\K.E = \frac{1}{2} \times 100 \times (1.5t^2 + 2) ^2\\\\K.E = 50 (1.5t^2 + 2) ^2\\

We know that Force = mass \times acceleration

a = v'(t) = 1.5t^2 + 2\\a = 3t

F = m \times a\\F= m \times 3t\\F = 3tm

6 0
4 years ago
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