Essentially, an increase in mass means an increase in gravity, while a decrease in mass means a decrease in gravity. So if the Sun spontaneously lost half its mass (gasp, shudder, the horror!) then its gravitational pull on Earth would lessen as well, ultimately changing the very nature of our orbit around the Sun.
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The average radius(r) of each grain is r = 50 nanometers
= 50*10^-6 meters
Since it is spherical, so
Volume=(4/3)*pi*r^3
V= (4/3)*pi*(50*10^-6)^3
V=5.23599*10^-13 m^3
We are given the Density(ρ) =2600kg/m^3
We know that:
Density(p) = mass(m)/volume(V)
m = ρV
So the mass of a single grain is:
m = 5.23599*10^-13 * 2600 = 1.361357*10^-9 kg
The surface area of a grain is:
a = 4*pi*r^2
a = 4*pi*(50*10^-6)^2
a = 3.14*10^-8 m^2
Since we know the surface area and mass of a grain, the
conversion factor is:
1.361357*10^-9 kg / 3.14*10^-8 m^2
Find the Surface area of the cube:
cube = 6a^2
cube = 6*1.1^2 = 7.26m^2
multiply this by the converions ratio to get:
total mass of sand grains = (7.26 m^2 * 1.361357*10^-9 kg)
/ (3.14*10^-8 m^2)
total mass of sand grains = 0.3148 kg = 314.80 g
Answer:
Explanation:
a. Internal energy and the relative specific volume at 
are determined from A-17:
.
The relative specific volume at 
is calculated from the compression ratio:
#from this, the temperature and enthalpy at state 2, can be determined using interpolations 
and 
. The specific volume at can then be determined as:
Specific volume,:
The pressures at 
is:
.The thermal efficiency=> maximum temperature at 
can be obtained from the expansion work at constant pressure during 
b.Relative SV and enthalpy at are obtained for the given temperature with interpolation with data from A-17 :
Relative SV at 
is
=
Thermal efficiency occurs when the heat loss is equal to the internal energy decrease and heat gain equal to enthalpy increase;
Hence, the thermal efficiency is 0.563
c. The mean relative pressure is calculated from its standard definition:
Hence, the mean effective relative pressure is 674.95kPa
Kinetic energy= 1/2 m v^2
so... 1/2(1350)(12^2)
kinetic energy = 97200Joules
I think the answer is 2 hope it helps
