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Ierofanga [76]
4 years ago
8

An electron moves in the plane of this screen toward the top of the screen. A magnetic field is also in the plane of the screen

and directed toward the right. What is the direction of the magnetic force on the electron?
Physics
1 answer:
Ad libitum [116K]4 years ago
6 0

Answer: the direction of the magnetic force on the electron will be moving out of the screen, perpendicular to the magnetic field.

Explanation:

The magnetic force F on a moving electron at right angle to a magnetic field is given by the formula:

F = BqVSinØ

If an electron moves in the plane of this screen toward the top of the screen. A magnetic field is also in the plane of the screen and directed toward the right. Then, the direction of the magnetic force on the electron will be perpendicular to the magnetic field

According to the Fleming's left - hand rule, the direction of the magnetic force on the electron will be moving out of the plane of the screen.

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Snowboarder Jump—Energy and Momentum
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Answer:

THE ANSWER TERMS ARE DEFINED BLOW:-

Explanation:

MOMENTUM- IT IS THE ABILITY TO INCREASE OR DEVELOP CONSTANT FORCE.

KINETIC ENERGY:- IT IS THE ENERGY THAT A PRTICLE POSSES WHEN IT IS ACTUALLY IN MOTION.

POTENTIAL ENERGY:- IT IS THE ENERGY THAT A PARTICLE POSSES WHEN IT ACTUALLY IS IN RESTING STATE.

IN THIS ACIVITY THE SNOWBOARDER IS IN THE MOTION STATE THEREFORE HE POSSES KINETIC ENERGY AND TO MAINTAIN THAT KINEITC ENERG FOR A PERIOD OF TIME,MOMENTUM PLAYS IT'S ROLE.

4 0
3 years ago
The diagram shows a state of matter in a closed system before and after undergoing a
belka [17]

Answer:

the second one

Explanation:

3 0
3 years ago
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Why a pond of water appears shallower than it actually is?​
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The refraction of light at the surface of water makes ponds look shallower then they really are
3 0
3 years ago
A bicycle has a momentum of 36 kg* m/s and a very!I city of 4 m/s.What is the mass of the bicycle?
Strike441 [17]

p = 36 kgm/s

v = 4m/s

we know that,

p = mv

so,

m =  \frac{p}{v}

m  =  \frac{36}{4}

m = 9kg

8 0
3 years ago
An automobile can be considered to be mounted on four identical springs as far as vertical oscillations are concerned. The sprin
tresset_1 [31]

Answer:

a) 120341 N/m

b) 1.432 Hz

Explanation:

Given that

Frequency of oscillations of spring, F = 3.27 Hz

Mass of the car, m = 1140 kg

Average mass of passengers, M = 68 kg

The mass on each spring,

m = 1/4 m,

m = 1140 / 4

m = 285 kg

The spring constant on each spring, k is

ω = √(k/m), also,

ω = 2πf, so that

2πf = √(k/m)

If we square both sides, then

4π²f² = k/m

k = 4π²f²m if we substitute, we have

k = 4 * 3.142² * 3.27² * 285

k = 120341 Nm

Since the mass of each person is 68 kg, then the total mass of all passengers would be

68 * 5 = 340 kg

Thus, the total mass of the oscillating system is,

mass of passengers + mass of car

340 kg + 1140 kg

M(total) = 1480 kg

To get the vibrating frequency, we substitute for values in the equation

2πf = √(k/m)

F = 1/2π * √(k/m)

F = 1/2π * √(120341 / 1480)

F = 1/2π * √81.31

F = 0.1591 * 9

F = 1.432 Hz

7 0
4 years ago
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