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dexar [7]
3 years ago
10

Fluorin is often added to drinking water and toothpaste

Chemistry
2 answers:
Svetradugi [14.3K]3 years ago
4 0
This is true i think if that is a question
liq [111]3 years ago
4 0
This false. The correct answer is fluoride.
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W7L5 Stoichiometry Practice 2
Rzqust [24]

Answer:

.079 moles of Nirogen gas (N2)

Explanation:

You can see from the equaton that each ONE mole of N2 produces TWO moles of NH3.

 Find the number of moles of NH3 produced.

    Using Periodic Table : Mole wt of NH3 = 17 gm/mole

          2.7 gm / 17 gm/mole = .1588 moles

      One half as many moles of N2 are needed  = .079 moles

6 0
2 years ago
Please help Me I really need it
butalik [34]
Can you show the question that goes with those answer pls
7 0
3 years ago
Write the equation for the neutralization reaction in which barium chloride is the salt formed. Show the reaction in which the f
frutty [35]

Answer:

2 HCl + Ba(OH)₂ ⇒ BaCl₂ + 2 H₂O

Explanation:

In a complete neutralization reaction, an acid reacts with a base to form neutral salt and water. To form barium chloride, hydrochloric acid (acid) reacts with barium hydroxide  (base). The balanced chemical equation is:

2 HCl + Ba(OH)₂ ⇒ BaCl₂ + 2 H₂O

8 0
3 years ago
Why is it important for scientists to review and repeat the work of other scientists
guapka [62]

Answer:

Accuracy

Explanation:

It is important for scientists to review the work of other scientists, so they can be sure there are no mistakes or lack of judgement. They repeat to compare results to make hypotheses.

3 0
3 years ago
In a science lab, a student heats up a chemical from 10 °C to 25 °C which requires thermal energy of 30000 J. If mass of the obj
olganol [36]

Answer:

The specific heat capacity of the object is 50 J/g°C ( option 4 is correct)

Explanation:

Step 1: Data given

Initial temperature = 10.0 °C

Final temperature = 25.0 °C

Energy required = 30000 J

Mass of the object = 40.0 grams

Step 2: Calculate the specific heat capacity of the object

Q = m* c * ΔT

⇒With Q = the heat required = 30000 J

⇒with m = the mass of the object = 40.0 grams

⇒with c = the specific heat capacity of the object = TO BE DETERMINED

⇒with ΔT = The change in temperature = T2 - T2 = 25.0 °C - 10.0°C = 15.0 °C

30000 J = 40.0 g * c * 15.0 °C

c = 30000 J / (40.0 g * 15.0 °C)

c = 50 J/g°C

The specific heat capacity of the object is 50 J/g°C ( option 4 is correct)

3 0
3 years ago
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