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dexar [7]
2 years ago
10

Fluorin is often added to drinking water and toothpaste

Chemistry
2 answers:
Svetradugi [14.3K]2 years ago
4 0
This is true i think if that is a question
liq [111]2 years ago
4 0
This false. The correct answer is fluoride.
You might be interested in
Do all objects emit electromagnetic waves?
kherson [118]

Answer:

no, not all objects emit electromagnet waves.

Explanation: because lets say the object is carpet it has no magnetic waves in it so not all objects do.

6 0
3 years ago
In which groups of the modern periodic table are very active metals and very active non-metals placed?​
eimsori [14]

Answer:

group 1 and are called Alkali metals. Similarly, very active non-metals are placed in group 17

Explanation:

5 0
2 years ago
How much thermal energy is added to 10.0 g of ice at −20.0°C to convert it to water vapor at 120.0°C?
Sonbull [250]

Answer:

7479 cal.

31262.2 joules

Explanation:

This is a calorimetry problem where water in its three states changes from ice to vapor.

We must use, the calorimetry formula and the formula for latent heat.

Q = m . C . ΔT

Q = Clat . m

First of all, let's determine the heat for ice, before it melts.

10 g . 0.5 cal/g°C ( 0° - (-20°C) = 100 cal

Now, the ice has melted.

Q = Clat heat of fusion . 10 g

Q = 79.7 cal/g . 10 g → 797 cal

We have water  at 0°, so this water has to receive heat until it becomes vapor. Let's determine that heat.

Q = m . C . ΔT

Q = 10 g . 1 cal/g°C (100°C - 0°C) → 1000 cal

Water is ready now, to become vapor so let's determine the heat.

Q = Clat heat of vaporization . m

Q = 539.4 cal/g . 10 g → 5394 cal

Finally we have vapor water, so let's determine the heat gained when this vapor changes the T° from 100°C to 120°

Q = m . C . ΔT

Q = 10 g . 0.470 cal/g°C . (120°C - 100°C) → 94 cal

Now, we have to sum all the heat that was added in all the process.

100 cal + 797 cal + 1000 cal + 5394 cal + 94 cal =7479 cal.

We can convert this unit to joules, which is more acceptable for energy terms.

1 cal is 4.18 Joules.

Then, 7479 cal are (7479 . 4.18) = 31262.2 joules

6 0
3 years ago
3. Determine the enthalpy of formation for propane. 3C(s, gr) + 4H2(g) ---> C3H2(g) CzH3(g) AH = -2219.9 kJ C(s, gr) AH = -39
Mars2501 [29]

Answer:

b I hope this is right good luck

7 0
3 years ago
What is the mass of 1.7 × 1023 atoms of zinc (Zn)?
Rudiy27

Number of moles is defined as the ratio of given mass in g to the molar mass.

The mathematical formula is:

Number of moles = \frac{given mass in g}{molar mass}   (1)

Number of zinc atoms is equal to 1.7\times10^{23}, by Avogadro number, number of moles can be calculated.

As, 1 mol=6.022\times10^{23} atoms, hence,

1.7\times10^{23}\times\frac{1 mol}{6.022\times10^{23} }

= 0.2822 mol

Now, from formula (1), calculate mass in g (molar mass of zinc = 65.4 g/mol)

0.2822 mol = \frac{mass in g}{65.4 g/mol}

mass in g  = {0.2822 mol \times 65.4 g/mol

= 18.45588 g

Thus, by rounding off the above number, it will come near about 19 g approximately.

Hence, option (C) is the correct answer.



 



8 0
3 years ago
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