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professor190 [17]
3 years ago
15

A chef makes a marinade by mixing red pepper flakes, dried onion flakes, and a ground ginger with soy sauce. He sets the marinad

e on the counter for a few minutes. When he returns, he must stir the marinade because the spices have settled to the bottom of the container.
answer: the mixture is a suspension
Chemistry
2 answers:
Sophie [7]3 years ago
6 0

Answer:

Explanation: suspension is the answer

Alisiya [41]3 years ago
3 0

Answer:

Suspension

Explanation:

This mixture is a simple suspension.

A suspension is a mixture of small insoluble particles of a solid in a liquid or gas. Here, it is insoluble particles in liquid.

  • Suspensions are settle on standing this is why they have to be mixed again.
  • The particles do not pass through ordinary filter paper.
  • They are usually cloudy and have an opaque color.
  • The marinade is simply a suspension.
  • It is not a solution because they do not settle on standing.
  • Also, colloids do not settle on standing.
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Given the E0 values of the following two half-reactions: Zn  Zn2+ + 2e- E0 = 0.763 volt Fe  Fe2+ + 2e- E0 = 0.441 volt a) Writ
34kurt

<u>Answer:</u>

<u>For a:</u> The balanced chemical equation is written below.

<u>For b:</u> The corrosion of iron pipe will take place in the presence of zinc.

<u>For c:</u> Zinc will not protect iron pipe from corrosion.

<u>Explanation:</u>

  • <u>For a:</u>

The given half reaction follows:

The substance having highest positive E^o potential will always get reduced and will undergo reduction reaction. Here, zinc will undergo reduction reaction will get reduced.

<u>Oxidation half reaction:</u>  Zn\rightarrow Zn^{2+}+2e^-;E^o_{Zn^{2+}/Zn}=-0.763V

<u>Reduction half reaction:</u>  Fe+2e^-\rightarrow Fe;E^o_{Fe^{2+}/Fe}=-0.441V

The balanced chemical equation follows:

Fe+Zn^{2+}\rightarrow Fe^{2+}+Zn

  • <u>For b:</u>

For a reaction to be spontaneous (thermodynamically feasible) , the standard electrode potential must be positive.

To calculate the E^o_{cell} of the reaction, we use the equation:

E^o_{cell}=E^o_{cathode}-E^o_{anode}

Substance getting oxidized always act as anode and the one getting reduced always act as cathode.

Calculating the E^o_{cell} using above equation, we get:

E^o_{cell}=-0.441-(-0.763)=0.322V

As, the EMF is coming out to be positive, the reaction will be thermodynamically feasible and corrosion of iron pipe will take place in the presence of zinc.

  • <u>For c:</u>

As, the EMF of the cell is positive, the zinc will not protect the iron pipe from corrosion and the reaction will take place.

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Explanation:

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