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3 years ago

6

Which of these particles are lost in the oxidation process ?

2 answers:

elena-14-01-66 [18.8K]3 years ago

8 0

The answer is electrons !. Hope it helps !! :)

Vlad1618 [11]3 years ago

6 0

The correct answer is

Electrons

:)

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How many moles in 44.7 kg of carbon dioxide

slava [35]

Answer:

What is the number of moles of carbon present in 44 grams of carbon dioxide? One. 44 grams is a mole of carbon dioxide and there is one carbon atom in CO 2 so there is one mole of carbon. That’s how chemistry works.

Explanation:

What is the number of moles of carbon present in 44 grams of carbon dioxide? One. 44 grams is a mole of carbon dioxide and there is one carbon atom in CO 2 so there is one mole of carbon. That’s how chemistry works.

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2 years ago

tekilochka [14]

Explanation:

balance the equation ...HCl,Ba(OH) and BaCl2 are aqueous

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3 years ago

A certain substance X has a normal freezing point of -6.4 C and a molal freezing point depression constant Kf= 3.96 degrees C.kg

Brut [27]

Answer: $1.0\times 10^2g$

Explanation:

Depression in freezing point is given by:

$\Delta T_f=i\times K_f\times m$

$\Delta T_f=T_f^0-T_f=(-6.4-(13.6))^0C=7.2^0C$ = Depression in freezing point

i= vant hoff factor = 1 (for non electrolyte like urea)

$K_f$ = freezing point constant = $3.96^0C/m$

m= molality

$\Delta T_f=i\times K_f\times \frac{\text{mass of solute}}{\text{molar mass of solute}}\times \text{weight of solvent in kg}}$

Weight of solvent (X)= 950 g = 0.95 kg

Molar mass of non electrolyte (urea) = 60.06 g/mol

Mass of non electrolyte (urea) added = ?

$7.2=1\times 3.96\times \frac{xg}{60.06 g/mol\times 0.95kg}$

$x=1.0\times 10^2g$

Thus $1.0\times 10^2g$ urea was dissolved.

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3 years ago

A 42.0 mL sample of an NaOH solution is placed in a flask with a few drops of phenolphthalein (indicator). If 11.7 mL of a 0.325

olganol [36]

Please like if you get the answer :)

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2 years ago

Can you create the needed environment on earth to stop an atom completely

Tresset [83]

<span>Practically, the work needed to remove heat from a gas increases the colder.</span>

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3 years ago