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maw [93]
3 years ago
8

Which of the following is made up of only one type of atom? 1) NO 2) He 3)CO 4)MgS

Chemistry
1 answer:
olga55 [171]3 years ago
5 0
2)He is made up of one atom
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PPLLLZZZ HHEEEELLLPPPP​
masya89 [10]

Answer:

B) Cell Membrane

Explanation:

A) Chloroplasts are NOT in all cells, A is incorrect

C) Centrioles are for cell division, C is not correct

D) Cell walls are NOT in all cells, D is not correct

B) the cell membrane is responsible for materials traveling into and out of the cells to maintain homeostasis

5 0
4 years ago
What is the melting point of gallium?
Alenkinab [10]
The melting point of gallium is 85.59°F (29.77°C).
8 0
3 years ago
Read 2 more answers
What tool(s) does God give us to help us in our everyday lives? PLZ HURRY!!!!!!!!!!!!!
romanna [79]

Answer:

Life

Explanation:

With out him we wouldn't live

5 0
4 years ago
For the balanced chemical reaction
musickatia [10]

Answer:

150

Explanation:

  • C₄H₂OH + 6O2 → 4CO2 + 5H₂O

We can <u>find the equivalent number of O₂ molecules for 100 molecules of CO₂</u> using a <em>conversion factor containing the stoichiometric coefficients of the balanced reaction</em>, as follows:

  • 100 molecules CO₂ * \frac{6moleculesO_2}{4moleculesCO_2} = 150 molecules O₂

150 molecules of O₂ would produce 100 molecules of CO₂.

5 0
3 years ago
Typical "hard" water contains about 2.0 x 10–3 mol of Ca2+ per liter. Calculate the maximum concentration of fluoride ion that c
malfutka [58]

Answer:

[F^-]_{max}=4x10{-3}\frac{molF^-}{L}

Explanation:

Hello,

In this case, for the described situation, we infer that calcium reacts with fluoride ions to yield insoluble calcium fluoride as shown below:

Ca^{+2}(aq)+2F^-(aq)\rightleftharpoons CaF_2(s)

Which is typically an equilibrium reaction, since calcium fluoride is able to come back to the ions. In such a way, since the maximum amount is computed via stoichiometry, we can see a 1:2 mole ratio between the ions, therefore, the required maximum amount of fluoride ions in the "hard" water (assuming no other ions) turns out:

[F^-]_{max}=2.0x10^{-3}\frac{molCa^{2+}}{L}*\frac{2molF^-}{1molCa^{2+}}  \\

[F^-]_{max}=4x10{-3}\frac{molF^-}{L}

Best regards.

8 0
3 years ago
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