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goblinko [34]
3 years ago
9

A variation of the acetamidomalonate synthesis can be used to synthesize threonine. The process involves the following steps: Et

hoxide ion deprotonates diethyl acetamidomalonate, forming enolate anion 1; Enolate anion 1 makes a nucleophilic attack on acetaldehyde, forming tetrahedral intermediate 2; Protonation of the oxyanion forms alcohol 3; Acid hydrolysis yields dicarboxyamino alcohol 4; Decarboxylation leads to the final amino acid. Write out the mechanism on a separate sheet of paper, and then draw the structure of tetrahedral intermediate 2.

Chemistry
1 answer:
ipn [44]3 years ago
7 0

Answer:

See figure 1

Explanation:

For this reaction, we have the production of a carbanion as the first step. The base "ethoxide" can remove a hydrogen-producing a negative charge in the carbon (<u>enolate anion 1</u>). Then this negative charge can attack the carbon of the carbonyl group in the molecule acetaldehyde and the <u>tetrahedral intermediate 2</u> is form. In the next step, we have the protonation of the oxygen to produce <u>alcohol 3</u>. A continuation we have the hydrolysis of the ester groups to produce the <u>Dicarboxyamino alcohol</u> and finally, we have a decarboxylation reaction we will produce the amino acid <u>Threonine</u>.

To further explanations see figure 1

I hope it helps!

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ser-zykov [4K]

Answer:

0.52 mol

Explanation:

Using the general gas equation formula:

PV = nRT

Where;

P = pressure (atm)

V = volume (Liters)

n = number of moles (mol)

R = gas law constant (0.0821 Latm/molK)

T = temperature (K)

At STP (standard temperature and pressure), temperature of a gas is 273K, while its pressure is 1 atm

Using PV = nRT

n = PV/RT

n = (1 × 11.74) ÷ (0.0821 × 273)

n = 11.74 ÷ 22.41

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Answer:

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Explanation:

Hello there!

In this case, it is widely known that ions are classified as positive cations and negative anions, since the former is produced when a metal loses electrons and the latter when a nonmetal gains electrons; in such a way, the correct choice is:

B) Cations lose electrons having a charge of positive.

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