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3 years ago

The light we see coming from the moon is which type of light from the sun?

Chemistry

2 answers:

GuDViN [60]3 years ago

8 0

Answer:

Reflective

Explanation:

Depending on the location of the moon in its orbit will determine how much the moon is capable of reflecting.

Hope this helps!

svetoff [14.1K]3 years ago

4 0

Answer:

the attribution of a personal nature or human characteristics to something nonhuman, or the representation of an abstract quality in human form.

Explanation:

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Ammonia will decompose into nitrogen and hydrogen at high temperature. An industrial chemist studying this reaction fills a tank

Masja [62]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The concentration equilibrium constant is $K_c = 14.39$

Explanation:

The chemical equation for this decomposition of ammonia is

$2 NH_3$ ↔ $N_2 + 3 H_2$

The initial concentration of ammonia is mathematically represented a

$[NH_3] = \frac{n_1}{V_1} = \frac{29}{75}$

$[NH_3] = 0.387 \ M$

The initial concentration of nitrogen gas is mathematically represented a

$[N_2] = \frac{n_2}{V_2}$

$[N_2] = 0.173 \ M$

So looking at the equation

Initially (Before reaction)

$NH_3 = 0.387 \ M$

$N_2 = 0 \ M$

$H_2 = 0 \ M$

During reaction(this is gotten from the reaction equation )

$NH_3 = -2 x$ (this implies that it losses two moles of concentration )

$N_2 = + x$ (this implies that it gains 1 moles)

$H_2 = +3 x$ (this implies that it gains 3 moles)

Note : x denotes concentration

At equilibrium

$NH_3 = 0.387 -2x$

$N_2 = x$

$H_2 = 3 x$

Now since

$[NH_3] = 0.387 \ M$

$x= 0.387 \ M$

$H_2 = 3 * 0.173$

$H_2 = 0.519 \ M$

$NH_3 = 0.387 -2(0.173)$

$NH_3 = 0.041 \ M$

Now the equilibrium constant is

$K_c = \frac{[N_2][H_2]^3}{[NH_3]^2}$

substituting values

$K_c = \frac{(0.173) (0.519)^3}{(0.041)^2}$

$K_c = 14.39$

3 0

3 years ago

Ammonia gas decomposes to form nitrogen and hydrogen gases. NH3(g) → N2(g) 3H2(g) If the nitrogen gas is collected in a rigid 2

sveticcg [70]

Decomposition is a chemical reaction that breaks the reactant into two or more products. Moles of nitrogen gas $(\rm N_{2})$ in the cylinder is 1.63 moles.

<h3>What is the ideal gas equation?</h3>

The ideal gas equation states the relation of the hypothetical ideal gas according to the pressure, volume, temperature and moles of the gas. It is given by,

$\rm PV = nRT$

Where,

Pressure (P) = 2000 kPa

Volume (V) = 2L

Temperature (T) = 295 K

Gas constant (R)= 0.08206

Substituting values in the equation:

$\begin{aligned} \rm n &= \rm \dfrac{PV}{RT}\\\\&= \dfrac{2000 \times (\dfrac{1}{101.325}) \times 2}{0.08206 \times 295}\\\\&= 1.63\;\rm mol\end{aligned}$