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3 years ago

A light ray moving at a 54.3 deg

Physics

1 answer:

MrMuchimi3 years ago

3 0

Answer:

$45.25^{\circ}$

Explanation:

Applying Snell's law

$n_1sin\theta_1 = n2*sin\theta_2\\1.33*sin(54.3) = 1.52*sin\theta_2\\sin\theta_2 = 1.33*0.81208353/1.52 = 0.71057\\\theta_2=sin^{-1} (0.71057)\\\theta_2 = 45.25^{\circ}$

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Can the velocity of a body revese the direction when acceleration is constant?

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Answer:

Yes, the velocity of the object can reverse direction when its acceleration is constant. For example consider that the velocity of any object at any time t is given as: ... At At t = 0 sec, the magnitude of velocity is 2m/s and is moving in the forward direction i.e.v (t) = -2.

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3 years ago

Jerry runs 60 meters east and then 20 meters west in 10

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3 years ago

What are (a) the energy of a photon corresponding to wavelength 6.0 nm, (b) the kinetic energy of an electron with de Broglie wa

dlinn [17]

Explanation:

Given that,

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Using formula of energy

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(b). We need to calculate the kinetic energy of an electron

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(c). We need to calculate the energy of photon

Using formula of energy

$E = \dfrac{hc}{\lambda}$

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Using formula of kinetic energy

$\lambda=\dfrac{h}{\sqrt{2mE}}$

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$E=6.709\times10^{-9}\ J$

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3 years ago

What is the purpose of a rearview mirror in a car?

Shalnov [3]

The third choice.

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3 years ago

Read 3 more answers

The flatbed truck is traveling at the constant speed of 60 km/h up the 15‐percent grade when the 100‐kg crate which it carries i

Alexus [3.1K]

Answer:

μ = 0.309

Explanation:

coefficient of kinetic friction is defined as the ratio of two forces, friction force and the normal force acting on the object.

θ = arctan(15/100)= 8.531⁰

In the vertical direction:

N = mgcosθ = 100 *9.8 *cos(8.531) = 970N

law of conservation of energy implies

mgsinθ - μNx = 1/2m(v₂²-v₁²)

100*9.8*sin (8.531) - μ(970*2) = 1/2(100)(0²-3²)

150.6 - 1940μ = 450

- 1940μ = -600.6

μ = 0.309

7 0

3 years ago