Answer:
B
Explanation:
Because it has to increase
Answer:
This is an inelastic collision. This means, unfortunately, that KE cannot save you, at least in the problem's current form.
Let's see what conservation of momentum in both directions does ya:
Conservation in the x direction:
Only 1 object here has a momentum in the x direction initally.
m1v1i + 0 = (m1 + m2)(vx)
3.09(5.10) = (3.09 + 2.52)Vx
Vx = 2.81 m/s
Explanation:
Conservation in the y direction:
Again, only 1 object here has initial velocity in the y:
0 + m2v2i = (m1 +m2)Vy
(2.52)(-3.36) = (2.52 + 3.09)Vy
Vy = -1.51 m/s
++++++++++++++++++++
Now that you have Vx and Vy of the composite object, you can find the final velocity by doing Vf = √Vx^2 + Vy^2)
Vf = √(2.81)^2 + (-1.51)^2
Vf = 3.19 m/s
The answer is C hope it helped
Answer:
A. China rose
B. Methyl red
C. Phenolphthalein
Explanation:
An indicator is a substance used to detect the presence of an acid or base as characterized by the indicators color change. An indicator can either be natural or synthetic depending on whether it is obtained from naturally occurring substance (natural) or synthesized in a laboratory (synthetic).
A. China rose is a type of natural indicator that turns deep PINK or MAGENTA in the presence of an acid or GREEN in the presence of a base.
B. Methyl red is a synthetic Indicator that turns RED in the presence of an acid or YELLOW in the presence of a base.
C. Phenolphthalein is an organic dye that is originally colorless but turns PINK in the presence of a base but remains colorless in the presence of an acid or neutral substance.
Answer:
the energy comes from the increase in the electric field
Explanation:
The capacitance is
C = ε₀ A / d
The electric charge on the condenser plates
Q = C ΔV
The stored electrical energy is
U = ½ C ΔV²
ΔV = E d
U = ½ (ε₀ A / d) (E d)²
U = ½ ε₀ A d E²
We see that the stored energy is proportional to the square of the electric field, so the capacitor can increase its energy with increasing voltage
In short, the energy comes from the increase in the electric field
