Answer:
112.5 J
Explanation:
I calculated it by K/G BY M/S TO POTENTIAL ENERGY.
Answer:
i think that the answer might be be C. one day. because it last about 4 to 6 hours
Answer:
Ecu/Eag = 0.46
Explanation:
E = PI/A
Ecu = Pcu × I/A
Pcu = 1.72×10^-8 ohm-meter
r = 0.8 mm = 0.8/1000 = 8×10^-4 m
A = πr^2 = π×(8×10^-4)^2 = 6.4×10^-7π
Ecu = 1.72×10^-8I/6.4×10^-7π = 0.026875I/1
Eag = Pag × I/A
Pag = 1.47×10^-8 ohm-meter
r = 0.5 mm = 0.5/1000 = 5×10^-4 m
A = πr^2 = π × (5×10^-4)^2 = 2.5×10^-7π
Eag = 1.47×10^-8I/2.5×10^-7π = 0.0588I/π
Ecu/Eag = 0.026875I/π × π/0.0588I = 0.46
resultant force = thrust – weight
acceleration = resultant force (newtons, N) divided by mass (kilograms, kg).
Acceleration = resultant force divided by mass
53N/0.56
=94.64 approximately 95
= 95m/s^2
This means that, every second, the speed of the rocket increases by 95m/s2
the S.I unit of Acceleration is meter per second square.
