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jekas [21]
2 years ago
14

A 1500 kg car traveling 5.0 m/s collides head on with a 3000 kg truck traveling

Physics
1 answer:
Setler [38]2 years ago
6 0
  • m1=1500kg
  • m_2=3000kg
  • v_1=5m/s
  • v_2=7m/s

Using law of conservation of momentum

\\ \sf\Rrightarrow m_1v_1-m_2v_2=(m1+m2)v_3

\\ \sf\Rrightarrow 1500(5)-3000(7)=(1500+3000)v_3

\\ \sf\Rrightarrow 7500-21000=4500v_3

\\ \sf\Rrightarrow -13500=4500v_3

\\ \sf\Rrightarrow v_3=-3m/s

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Answer:

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From the question we are told that

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Here  KE_i is the kinetic energy of the space probe due to its initial speed which is mathematically represented as

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Generally from the law energy conservation we have that

        T__{E}} =  KE_p

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