Answer:
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Answer:
0.325 N
Explanation:
From the question,
T = 4π²rm/t²............................ Equation 1
Where T = Tension, r = radius or length of the string, m = mass of the string, t = time.
Given: r = 2.4 m, m = 15 g = 0.015 kg, t = 2.09 s.
Constant: π = 3.14
Substitute these values into equation 1
T = 4(3.14²)(2.4)(0.015)/2.09²
T = 1.4198/4.3681
T = 0.325 N
Answer:
The correct option is;
C. 1 mile clear of clouds
Explanation:
Given that the indicated airspace location is at or below 700 feet AGL therefore, it is taken as being in the region of a class G airspace which covers the airspace regions from the base up to and equal to 1,200 feet beneath the class E airspace and the requirement for VFR flight for class G are 1 mile and clear of clouds.