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MrRissso [65]
3 years ago
5

A 36.3 kg cart has a velocity of 3 m/s. How much kinetic energy does the object have?

Physics
1 answer:
uysha [10]3 years ago
7 0

Answer:

163.35

__________________________________________________________

<u>We are given:</u>

Mass of the object (m) = 36.3 kg

Velocity of the object (v) = 3 m/s

<u>Kinetic Energy of the object:</u>

We know that:

Kinetic Energy = 1/2(mv²)

KE = 1/2(36.3)(3)²            [replacing the variables with the given values]

KE = 18.15 * 9

KE = 163.35 Joules

Hence, the cart has a Kinetic Energy of 163.35 Joules

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A girl and her bicycle have a total mass of 40 kg. At the top of the hill her speed is 5.0 m/s. The hill is 10 m high and 100 m
Serhud [2]

Answer:

v =   11 m/s   is her final speed

Explanation:

work done by gravity = m g Δh =   40×9.8×10   = 3920 Joules

Work done by friction = - force×distance =   - 20×100   =   - 2000 Joules

[minus sign because friction force is opposite to the direction of motion]

Initial K.E. = (1/2) m u^2 = (1/2) × 40 × 5^2   = 500 Joules

Now, by work energy theorem

Work done = change in kinetic energy.

Final K.E. = initial K.E. + total work =    500 + 3920 - 2000  = 2420 Joules

Now, Final K.E. = (1/2) m v^2  [final speed being v= speed at the bottom]

⇒  2420 = (1/2)×40×v^2

   ⇒  121 = v^ 2

  v =   11 m/s   is her final speed

5 0
3 years ago
When does heat transfer through convection stop within gas?
Alekssandra [29.7K]

Answer:

D. When the temperature of the gas is the same throughout

Explanation:

7 0
3 years ago
Identify the labeled parts in the figure.
ad-work [718]

Answer:

Chemical symbols Al, O, H, O or a,c,f,h.

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5 0
3 years ago
A ball is spun around in circular motion such that it completes 50 rotations in 25 s. What is the frequency of its rotation? 2.
Elis [28]

Answer:

1. f = 2 Hz

2. f = 0.011 Hz

3. f = 0.067 Hz

4. t = 4 s

Explanation:

1. The frequency of rotation is given by:

f = \frac{\omega}{2\pi}

Where:

ω: is the angular speed = 50 rotations (revolutions) in 25 s.

We need to convert the units of ω.

\omega = \frac{50 rev}{25 s}*\frac{2\pi rad}{1 rev} = 4\pi rad/s

Now, the frequency is:

f = \frac{4\pi rad/s}{2\pi} = 2 Hz

2. The frequency is:

We know:

5 laps = 5 revolutions

t: time = 450 s

f = \frac{\omega}{2\pi} = \frac{\frac{5 rev}{450 s}*\frac{2\pi rad}{1 rev}}{2\pi} = 0.011 Hz    

3. The frequency of the pendulum is:

f = \frac{\omega}{2\pi} = \frac{\frac{1 rev}{15 s}*\frac{2\pi rad}{1 rev}}{2\pi} = 0.067 Hz

4. We have:

θ: number of revolutions = 48 rev

f = 12 Hz

t =?

The time can be calculated as follows:

f = \frac{\omega}{2\pi} = \frac{\theta}{2\pi t}

t = \frac{\theta}{2\pi f} = \frac{48 rev*\frac{2\pi rad}{1 rev}}{2\pi*12 Hz} = 4 s

I hope it helps you!

4 0
3 years ago
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