Answer: The correct answer is option (A).
Explanation
Ampacity is defined as the maximum amount of the current carried by the conductor continuously without exceeding its temperature rating.
The ampacity of the wire of the heater is 30 A .And this means that wire is capable of conducting current of maximum amount of 30 Ampere through it without exceeding its temperature rating.
Hence, the correct answer is option is (A).
Answer:
Explanation:
According to Coulomb's law, the magnitude of the electric force between two point charges is directly proportional to the product of the magnitude of both charges and inversely proportional to the square of the distance that separates them:
Here k is the Coulomb constant. In this case, we have 
, 
and 
. Replacing the values:
The negative sign indicates that it is an attractive force. So, the magnitude of the electric force is:
Answer: 1018.26 m/s
Explanation:
Approaching the orbit of the Moon around the Earth to a circular orbit (or circular path), we can use the equation of the speed of an object with uniform circular motion:
Where:
is the speed of travel of the Moon around the Earth
is the Gravitational Constant
is the mass of the Earth
is the distance from the center of the Earth to the center of the Moon
Solving:
This is the speed of travel of the Moon around the Earth
Answer:
1.) 11 km/s
2.) 9.03 × 10^-5 metres
Explanation:
Given that an electron enters a region of uniform electric field with an initial velocity of 64 km/s in the same direction as the electric field, which has magnitude E = 48 N/C.
Electron q = 1.6×10^-19 C
Electron mass = 9.11×10^-31 Kg
(a) What is the speed of the electron 1.3 ns after entering this region?
E = F/q
F = Eq
Ma = Eq
M × V/t = Eq
Substitute all the parameters into the formula
9.11×10^-31 × V/1.3×10^-9 = 48 × 1.6×10^-19
V = 7.68×10^-18 /7.0×10^-22
V = 10971.43 m/s
V = 11 Km/s approximately
(b) How far does the electron travel during the 1.3 ns interval?
The initial velocity U = 64 km/s
S = ut + 1/2at^2
S = 64000×1.3×10^-6 + 1/2 × 8.4×10^12 × ( 1.3×10^-9)^2
S =8.32×10^-5 + 7.13×10^-6
S = 9.03 × 10^-5 metres
Answer:
9.81N
Explanation:
the force of attraction is given by
F=<u>GmM</u><u>/</u><u>R²</u><u> </u>
where m is mass of the body
M is mass of the earth
R is radius of the earth
G is the universal gravitational constant(6.67x10-¹¹)
hence we substitute the values in the formula.
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