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2 years ago

7

A 15 g ball at the end of 2.4 m string is swung in the horizontal circle. It revolves once every 2.09 s. What is the magnitude o

f the
string's tension ?

1 answer:

Mrrafil [7]2 years ago

3 0

Answer:

0.325 N

Explanation:

From the question,

T = 4π²rm/t²............................ Equation 1

Where T = Tension, r = radius or length of the string, m = mass of the string, t = time.

Given: r = 2.4 m, m = 15 g = 0.015 kg, t = 2.09 s.

Constant: π = 3.14

Substitute these values into equation 1

T = 4(3.14²)(2.4)(0.015)/2.09²

T = 1.4198/4.3681

T = 0.325 N

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