A 15 g ball at the end of 2.4 m string is swung in the horizontal circle. It revolves once every 2.09 s. What is the magnitude o f the
1 answer:
Answer:
0.325 N
Explanation:
From the question,
T = 4π²rm/t²............................ Equation 1
Where T = Tension, r = radius or length of the string, m = mass of the string, t = time.
Given: r = 2.4 m, m = 15 g = 0.015 kg, t = 2.09 s.
Constant: π = 3.14
Substitute these values into equation 1
T = 4(3.14²)(2.4)(0.015)/2.09²
T = 1.4198/4.3681
T = 0.325 N
You might be interested in
Answer:
maybe alternator..generator..
It is an example of liquid. if thats what you are asking for...
(3) 8.3 N/kg. The gravitational field strength at a point is the force per unit mass exerted on a mass placed at that point. So at the point where the Hubble telescope is, it is (9.1 x 10^4)N/(1.1 x 10^4 kg) = 8.3 N/kg
<span>C. Mao Zedong
2 is the answer have a nice day <3
