a worker uses a board that is 7 m long to pry up a bolder A small rock is used for the fulcrum and is placed 2.5 m from the resi
1 answer:
You might be interested in
The range of potential energies of the wire-field system for different orientations of the circle are -
θ U
0° 375 π x
90° 0
180° - 375 π x
We have current carrying wire in a form of a circle placed in a uniform magnetic field.
We have to the range of potential energies of the wire-field system for different orientations of the circle.
<h3>What is the formula to calculate the Magnetic Potential Energy?</h3>The formula to calculate the magnetic potential energy is -
U = M.B = MB cos
where -
M is the Dipole Moment.
B is the Magnetic Field Intensity.
According to the question, we have -
U = M.B = MB cos
We can write M = IA (I is current and A is cross sectional Area)
U = IAB cos
U = IπB cos
For = 0° →
U(Max) = MB cos(0) = MB = IπB = 5 × π ×
× 3 ×
=
375 π x .
For = 90° →
U = MB cos (90) = 0
For = 180° →
U(Min) = MB cos(0) = - MB = - IπB = - 5 × π ×
× 3 ×
=
- 375 π x .
Hence, the range of potential energies of the wire-field system for different orientations of the circle are -
θ U
0° 375 π x
90° 0
180° - 375 π x
To solve more questions on Magnetic potential energy, visit the link below-
#SPJ4
Answer:
3.416 m/s
Explanation:
Given that:
mass of cannonball = 72.0 kg
mass of performer = 65.0 kg
The horizontal component of the ball initially = 6.50 m/s
the final velocity of the combined system v = ????
By applying the linear momentum of conservation:
v = 3.416 m/s