Answer:
27.14 ohms
Explanation:
V = IR
V/I = R
1.9 v / .07 a = 27.14 ohms
Answer:
230.4 N
Explanation:
Applying,
F = kqq'/r²..................... Equation 1
Where F = Electric force, k = Coulomb's constant, q = charge in the ballon, q' = charge in the denium, r = distance between the charges.
From the question,
Given: q = -8.0×10⁻⁶ C, q' = +8.0×10⁻⁶ C, r = 0.05 m
Constant: k = 9×10⁹ Nm²/C²
Substitute these values into equation 1
F = (9×10⁹×8.0×10⁻⁶×8.0×10⁻⁶ )/0.05²
F = (576×10⁻³)/0.0025
F = 230.4 N.
Answer:
t = 0.319 s
Explanation:
With the sudden movement of the athlete a pulse is formed that takes time to move along the rope, the speed of the rope is given by
v = √T/λ
Linear density is
λ = m / L
λ = 4/20
λ = 0.2 kg / m
The tension in the rope is equal to the athlete's weight, suppose it has a mass of m = 80 kg
T = W = mg
T = 80 9.8
T = 784 N
The pulse rate is
v = √(784 / 0.2)
v = 62.6 m / s
The time it takes to reach the hook can be searched with kinematics
v = x / t
t = x / v
t = 20 / 62.6
t = 0.319 s
