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leva [86]
3 years ago
14

How does increased carbon dioxide affects the flow of energy in a closed system

Chemistry
1 answer:
DedPeter [7]3 years ago
4 0

Answer:

Weather and climate on Earth are determined by the amount and distribution of incoming radiation from the sun. For an equilibrium climate, outgoing longwave (infrared) radiation (OLR) necessarily balances the incoming absorbed solar radiation (ASR), so that the Net =ASR-OLR =0. There is a great deal of fascinating atmosphere, ocean and land phenomena that couple the ASR and OLR and the balance is only for the annual mean, not individual months or seasons. Incoming radiant energy may be scattered and reflected by clouds and aerosols, or absorbed in the atmosphere. The transmitted radiation is then either absorbed or reflected at the Earth’s surface. Radiant solar (shortwave) energy is transformed into sensible heat, latent energy (involving different water states), potential energy (involving gravity and height above the surface (or in the oceans, depth below)) and kinetic energy (involving motions) before being emitted back to space as longwave radiant energy. Energy may be stored for some time, transported in various forms, and converted among the different types, giving rise to a rich variety of weather or turbulent phenomena in the atmosphere and ocean. Moreover, the energy balance can be upset in various ways (so the Net ≠ 0), changing the climate and associated weather.

Explanation:

this should help

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Elodia [21]
Do you need help with something?
6 0
3 years ago
Read 2 more answers
if only 0.264 g of ca(oh)2 dissolves in enough water to give 0.178 l of aqueous solution at a given temperature, what is the ksp
Maurinko [17]

The ksp value for calcium hydroxide at this temperature is 5.20 × 10⁻⁶.

<h3>What is ksp?</h3>

Ksp is an equilibrium constant of a solid substance dissolved in a liquid solution.

Given that, the volume of water is 0.178 l, 0.264 g of Ca(OH)² dissolves in enough water

The solution equilibrium is

Ca(OH)² = Ca + 2OH

The molar solubility is

0.186 / 74.00  / 0.230 = 0.0109 M

The ksp value will be

Ksp = (s) (2S)²

Putting the values in the formula

(0.0109) x (2 x 0.0109)² = 5.20 × 10⁻⁶.

Thus, the ksp value for calcium hydroxide is 5.20 × 10⁻⁶.

To learn more about ksp value, refer to the link:

brainly.com/question/27132799

#SPJ4

8 0
1 year ago
A solution of aqueous ammonium sulfate has a mass of 482 grams. Calculate the mass of ammonium sulfate in solution if the mass p
umka2103 [35]

Answer:

The answer to your question is the mass of solute = 53.5 g

Explanation:

Data

mass of solution = 482 g

mass of solute = ?

mass percent = 11.1 %

Mass percent is a unit of concentration. It measures the mass of the solute divided by the total mass of the solution

Process

1.- Write the formula

        Mass percent = mass of solute / mass of solution x 100

-Solve for mass of solute

          mass of solute = Mass percent x mass of solution / 100

2.- Substitution

          mass of solute = 11.1 x 482 / 100

3.- Simplification

          mass of solute = 5350.2 / 100

4.- Result

          mass of solute = 53.5g

6 0
3 years ago
Which element has 1s2s2p3s3p electron configuration?
Rus_ich [418]
To answer this problem, we need to count the electrons in the given configuration. The complete configuration is 1s2 2s2 2p6 3s2 3p6. There are 2+2+6+2+6 equal to 18 electrons. We find next the element with an atomic number of 18. That element is noble gas argon. 
6 0
3 years ago
Read 2 more answers
What is the maximum concentration of Ag⁺ that can be added to a 0.00750 M solution of Na₂CO₃ before a precipitate will form? (Ks
Firlakuza [10]

Answer:

\large \boxed{1.64\times 10^{-5}\text{ mol/L }}

Explanation:

Ag₂CO₃(s) ⇌2Ag⁺(aq) + CO₃²⁻(aq); Ksp = 8.10 × 10⁻¹²

                           2x      0.007 50 + x

K_{sp} =\text{[Ag$^{+}$]$^{2}$[CO$_{3}^{2-}$]} = (2x)^{2}\times 0.00750 = 8.10 \times 10^{-12}\\0.0300x^{2} = 8.10 \times 10^{-12}\\x^{2} = 2.70 \times 10^{-10}\\x = \sqrt{2.70 \times 10^{-10}} = \mathbf{1.64\times 10^{5}} \textbf{ mol/L}\\\text{The maximum concentration of Ag$^{+}$ is $\large \boxed{\mathbf{1.64\times 10^{-5}}\textbf{ mol/L }}$}

 

3 0
3 years ago
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