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3 years ago

How does increased carbon dioxide affects the flow of energy in a closed system

Chemistry

1 answer:

DedPeter [7]3 years ago

4 0

Answer:

Weather and climate on Earth are determined by the amount and distribution of incoming radiation from the sun. For an equilibrium climate, outgoing longwave (infrared) radiation (OLR) necessarily balances the incoming absorbed solar radiation (ASR), so that the Net =ASR-OLR =0. There is a great deal of fascinating atmosphere, ocean and land phenomena that couple the ASR and OLR and the balance is only for the annual mean, not individual months or seasons. Incoming radiant energy may be scattered and reflected by clouds and aerosols, or absorbed in the atmosphere. The transmitted radiation is then either absorbed or reflected at the Earth’s surface. Radiant solar (shortwave) energy is transformed into sensible heat, latent energy (involving different water states), potential energy (involving gravity and height above the surface (or in the oceans, depth below)) and kinetic energy (involving motions) before being emitted back to space as longwave radiant energy. Energy may be stored for some time, transported in various forms, and converted among the different types, giving rise to a rich variety of weather or turbulent phenomena in the atmosphere and ocean. Moreover, the energy balance can be upset in various ways (so the Net ≠ 0), changing the climate and associated weather.

Explanation:

this should help

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what is the molecular formula of the molecule thay has an empirical formula of CH20and a molar mass of 240.2 g/mol?

worty [1.4K]

C8H16O8

Explanation:

(CH2O)n=240.2

=12n+2n+16n=240.2

=30n=240.2

n=8

C8H16O8

4 0

3 years ago

Which mixture is homogeneous? a.soil b.salad dressing c.granola cereal d.milk

Hoochie [10]

The correct answer is D . Milk

6 0

3 years ago

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How do human beings prepare their food

Rudiy27

Well they buy food then they cook it then they eat it

3 0

3 years ago

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The dissociation of calcium carbonate has an equilibrium constant of Kp= 1.20 at 800°C. CaCO3(s) ⇋ CaO(s) + CO2(g)

Fed [463]

Explanation:

(a) Formula that shows relation between $K_{c}$ and $K_{p}$ is as follows.

$K_c = K_p \times (RT)^{-\Delta n}$

Here, $\Delta n$ = 1

Putting the given values into the above formula as follows.

$K_c = K_p \times (RT)^{-\Delta n}$

= $1.20 \times (RT)^{-1}$

= $\frac{1.20}{0.0820 \times 1073}$

= 0.01316

(b) As the given reaction equation is as follows.

$CaCO_{3}(s) \rightleftharpoons CaO(s) + CO_{2}(g)$

As there is only one gas so ,

$p[CO_{2}] = K_{p}$ = 1.20

Therefore, pressure of $CO_{2}$ in the container is 1.20.

(c) Now, expression for $K_{c}$ for the given reaction equation is as follows.

$K_{c} = \frac{[CaO][CO_{2}]}{[CaCO_{3}]}$

= $\frac{x \times x}{(a - x)}$

= \frac{x^{2}}{(a - x)}[/tex]

where, a = initial conc. of $CaCO_{3}$

= $\frac{22.5}{100} \times 9.56$

= 0.023 M

0.0131 = $\frac{x^{2}}{0.023 - x}$

x = 0.017

Therefore, calculate the percentage of calcium carbonate remained as follows.

% of $CaCO_{3}$ remained = $(\frac{0.017}{0.023}) \times 100$

= 75.46%

Thus, the percentage of calcium carbonate remained is 75.46%.

3 0

4 years ago

Please help! Thanks!

olya-2409 [2.1K]

Answer:

The deviations are :

The activation energy which changes with temperature
The arrhenius constant which depends on the temperature

Explanation:

There are deviations from the Arrhenius law during the glass transition in all classes of glass-forming matter.

The Arrhenius law predicts that the motion of the structural units (atoms, molecules, ions, etc.) should slow down at a slower rate through the glass transition than is experimentally observed.
In other words, the structural units slow down at a faster rate than is predicted by the Arrhenius law.
This observation is made reasonable assuming that the units must overcome an energy barrier by means of a thermal activation energy.
The thermal energy must be high enough to allow for translational motion of the units which leads to viscous flow of the material.

Both the Arrhenius activation energy and the rate constant k are experimentally determined, and represent macroscopic reaction-specific parameters that are not simply related to threshold energies and the success of individual collisions at the molecular level.
Consider a particular collision (an elementary reaction) between molecules A and B. The collision angle, the relative translational energy, the internal (particularly vibrational) energy will all determine the chance that the collision will produce a product molecule AB.
Macroscopic measurements of E(activation energy) and k(rate constant ) are the result of many individual collisions with differing collision parameters. They are averaged out to a macroscopic quantity.

6 0

3 years ago