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3 years ago

Question 5 (5 points)

Chemistry

2 answers:

Dima020 [189]3 years ago

6 0

Answer:

They Are all O's/oberavtions, because inference is using facts and reasoning, which is not the case here.

Explanation:

Natasha_Volkova [10]3 years ago

6 0

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Blank # 1 - Observation

Blank # 2 - Observation

Blank # 3 - Observation

Blank # 4 - Inference

Blank # 5 - Observation

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In Niels Bhor's model of the atom, electrons move

exis [7]

Bohrs model says that electrons move in fixed shells (which have fixed distances) around the nucleus of an atom.

5 0

3 years ago

Solve the question that follows using the equation for the conversion of Celsius to Fahrenheit. F=95(C)+32 On February 9, 1934,

ahrayia [7]

Answer:

Buffalo, NY was colder on February 9, 1934

Explanation:

Temperature is the measure of thermal energy present in a given substance. It is a physical property of a matter which can be measured on the Celsius scale (°C), Fahrenheit scale (°F), and Kelvin scale (K).

To convert Celsius (°C) to Fahrenheit (°F), we use the equation:

°F = 9/5 (°C) + 32

Given: On February 9, 1934,

Temperature in Buffalo, NY: T₁ = (- 29) °C

Temperature in Anchorage, AL: T₂ = 19 °F

To convert T₁ from °C to °F:

9/5 (- 29 °C) + 32 = (- 52.2) + 32 = (- 20.2) °F

So,

Temperature in Buffalo, NY: T₁ = (- 20.2) °F

Temperature in Anchorage, AL: T₂ = 19 °F

⇒ T₁ < T₂

Therefore, Buffalo, NY was colder on February 9, 1934.

4 0

3 years ago

As with other ionic compounds, potassium bromate, KBrO3, dissociates into ions when it dissolves in water. If 13.8 g of KBrO3 is

chubhunter [2.5K]

Answer:

ΔH of dissociation is 38,0 kJ/mol

Explanation:

The dissociation reaction of KBrO₃ is:

KBrO₃ → K⁺ + BrO₃⁻ 

This dissolution consume heat that is evidenced with the decrease in water temperature.

The heat consumed is:

q = CΔTm

Where C is specific heat of water (4,186 J/mol°C)

ΔT is the temperature changing (18,0°C - 13,0°C = 5,0°C)

And m is mass of water (150,0 mL ≈ 150,0 g)

Replacing, heat consumed is:

q = 3139,5 J ≡ 3,14 kJ

13,8 g of KBrO₃ are:

13,8 g×(1mol/167g) = 0,0826 moles

Thus, ΔH of dissociation is:

3,14kJ / 0,0826mol = 38,0 kJ/mol

I hope it helps!

3 0

3 years ago

When benzene (c6h6) reacts with bromine (br2) bromobenzene(c6h5br) is obtained: c6h6 + br2 → c6h5br + hbr what is the theoretica

saveliy_v [14]

Answer A) : We have to calculate the number of moles of Benzene involved in the reaction,

30 g / 78 moles of benzene = 0.384 moles

For bromine it will be the same process,

65 g / 159.8 moles = 0.406 moles

By observing the reaction given above we can say that the reaction ratio of bromine and benzene is 1 : 1

We need to find the mass of bromobenzene,

which should be, 6(12) + 5 (1)+ 79.90 = 156.9 g/mol

So, the mass of bromobenzene will be 156.9 g/mol X 0.3846 mol = 60.343 g

Hence the theoretical yield will be 60.34 g

Answer B) : To calculate the actual yield we have to divide it with theoretical yield.

(56.7g / 60.343 g ) X100% = 93.96 %

Here, we can say that we got 93.96 % of actual yield.

As we know it is impossible to get 100% yield in any reaction.

3 0

3 years ago

A student titrates 10.00 milliliters of hydrochloric acid of unknown molarity with 1.000 m naoh. it takes 21.17 milliliters of b

Dima020 [189]

Mole ratio for the reaction is 1:1
no of moles in NaOH that reacted= 1*21.17/1000=0.02117mols
molarity of HCl=0.02117*10/1000
=2.117M

4 0

3 years ago