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3 years ago

Did I start this right? If not what do I need to do? Thanks x

Chemistry

2 answers:

riadik2000 [5.3K]3 years ago

5 0

lily can u help me plz

Verdich [7]3 years ago

3 0

I'm pretty sure you started it right as long as you round your answers to a whole number, your good. You can find these on google or on the periodic table your teacher has provided for you.

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3 years ago

When naming ionic compounds the ______________ is named first.

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3 years ago

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1 year ago

What is the mass of a sample of water that takes 2000 kJ of energy to boil into steam at 373 K. The latent heat of vaporization

zzz [600]

Answer:

$\boxed{\text{889 g}}$

Explanation:

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$\begin{array}{rcl}2000 \times 10^{3} \text{ J} & = & m \times \dfrac{2.25 \times 10^{6} \text{ J}}{\text{1 kg}}\\\\m & = & \dfrac{2000 \times \times 10^{3}\text{ kg}}{2.25 \times 10^{6}}\\ & = & \text{0.889 kg}\\\\ & = & \text{889 g}\\\end{array}\\\text{The mass of water is $\boxed{\textbf{889 g}}$}$

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2 years ago

If Kc = 4.0×10−2 for PCl3(g)+Cl2(g)⇌PCl5(g) at 520 K , what is the value of Kp for this reaction at this temperature?

Flauer [41]

Here we have to get the $K_{p}$ of the reaction at 520 K temperature.

The $K_{p}$ of the reaction is 1.705 atm

We know the relation between $K_{p}$ and $K_{c}$ is $K_{p}=K_{c}(RT)^{N}$ , where $K_{p}$ = The equilibrium constant of the reaction in terms of partial pressure, $K_{c}$ = The equilibrium constant of the reaction in terms of concentration and N = number of moles of gaseous products - Number of moles of gaseous reactants.

Now in this reaction, PCl₃ + Cl₂ ⇄ PCl₅

Thus number of moles of gaseous product is 1, and number of moles of gaseous reactants are 2. Thus N = |1 - 2| = 1 mole

The given value of $K_{c}$ is 4.0×10⁻²

The molar gas constant, R = 0.082 L. Atm. mol⁻¹. K⁻¹ and temperature, T = 520 K.

On plugging the values in the equation we get,

$K_{p} = 4.0 X 10^{-2}(0.082X520)^{1}$

Or, $K_{p}$ = 1.705 atm

Thus, the $K_{p}$ of the reaction is 1.705 atm

7 0

3 years ago