For the reactants,
- The oxidation number of hydrogen = +1
- The oxidation number of oxygen = -2
- The oxidation number of arsenic = +5
- The oxidation number of carbon = +3
For the products,
- The oxidation number of hydrogen = +1
- The oxidation number of oxygen = -2
- The oxidation number of arsenic = +3
- The oxidation number of carbon = +4
Here, arsenic (+5 to +3) and carbon (+3 to +4) are the only oxidation numbers changing.
Note that an increase in oxidation number means electrons are lost. Thus oxidation is occurring, and a decrease in oxidation number means electrons are being gained, and thus reduction is occurring.
Also, the compound that contains the element being oxidized is the reducing agent, and the compound that contains the element being reduced is the oxidizing agent.
So, the answers are:
name of the element oxidized: Carbon
name of the element reduced: Arsenic
formula of the oxidizing agent: ![\text{H}_{3}\text{AsO}_{4}](https://tex.z-dn.net/?f=%5Ctext%7BH%7D_%7B3%7D%5Ctext%7BAsO%7D_%7B4%7D)
formula of the reducing agent: ![\text{H}_{2}\text{C}_{2}\text{O}_{4}](https://tex.z-dn.net/?f=%5Ctext%7BH%7D_%7B2%7D%5Ctext%7BC%7D_%7B2%7D%5Ctext%7BO%7D_%7B4%7D)
A conductor & a convection current.
To calculate the percent
of the radioactive isotope rhenium after 3 half-lives is
(1/2)^3 = 0.125 x 100 =
12.5%
We calculate that there
is 12.5% percent activity of the radioactive isotope.
<span>Radioactive isotope
other called as radioisotope, radioactive nuclide or radionuclide, in any of
the several species of the same chemical element with different masses whose
nuclei are unstable and dissipate excess energy by spontaneously emitting
radiation in the form of gamma, alpha and beta rays. Rhenium is a chemical element
and has an atomic number of 75. Its chemical symbol is Re. It is in the
third-row transition metal in group 7 of the periodic table.</span>
The majority of wind turbines consist of three blades mounted to a tower made from tubular steel. There are less common varieties with two blades, or with concrete or steel lattice towers. At 100 feet or more above the ground, the tower allows the turbine to take advantage of faster wind speeds found at higher altitudes.
Turbines catch the wind's energy with their propeller-like blades, which act much like an airplane wing. When the wind blows, a pocket of low-pressure air forms on one side of the blade. The low-pressure air pocket then pulls the blade toward it, causing the rotor to turn. This is called lift. The force of the lift is much stronger than the wind's force against the front side of the blade, which is called drag. The combination of lift and drag causes the rotor to spin like a propeller. So therefore your answer would be A.
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The question is incomplete, here is the complete question:
The given chemical equation follows:
![2H_2O\rightleftharpoons 2H_2+O_2](https://tex.z-dn.net/?f=2H_2O%5Crightleftharpoons%202H_2%2BO_2)
What is the equilibrium constant expression for the given system?
<u>Answer:</u> The expression of equilibrium constant for the given equation is ![K_{eq}=\frac{[H_2]^2[O_2]}{[H_2O]^2}](https://tex.z-dn.net/?f=K_%7Beq%7D%3D%5Cfrac%7B%5BH_2%5D%5E2%5BO_2%5D%7D%7B%5BH_2O%5D%5E2%7D)
<u>Explanation:</u>
Equilibrium constant is the ratio of concentration of products to the concentration of reactants each raised to the power their stoichiometric ratios. It is expressed as ![K_{eq}](https://tex.z-dn.net/?f=K_%7Beq%7D)
For a general chemical reaction:
![aA+bB\rightleftharpoons cC+dD](https://tex.z-dn.net/?f=aA%2BbB%5Crightleftharpoons%20cC%2BdD)
The expression for
is written as:
![K_{eq}=\frac{[C]^c[D]^d}{[A]^a[B]^b}](https://tex.z-dn.net/?f=K_%7Beq%7D%3D%5Cfrac%7B%5BC%5D%5Ec%5BD%5D%5Ed%7D%7B%5BA%5D%5Ea%5BB%5D%5Eb%7D)
The given chemical equation follows:
![2H_2O\rightleftharpoons 2H_2+O_2](https://tex.z-dn.net/?f=2H_2O%5Crightleftharpoons%202H_2%2BO_2)
The expression for
for above equation follows:
![K_{eq}=\frac{[H_2]^2[O_2]}{[H_2O]^2}](https://tex.z-dn.net/?f=K_%7Beq%7D%3D%5Cfrac%7B%5BH_2%5D%5E2%5BO_2%5D%7D%7B%5BH_2O%5D%5E2%7D)
Hence, the expression of equilibrium constant for the given equation is ![K_{eq}=\frac{[H_2]^2[O_2]}{[H_2O]^2}](https://tex.z-dn.net/?f=K_%7Beq%7D%3D%5Cfrac%7B%5BH_2%5D%5E2%5BO_2%5D%7D%7B%5BH_2O%5D%5E2%7D)