Answer:
P-value = 0.009997
Step-by-step explanation:
We are given the following in the question:
Sample size, n = 24
Nature of test: One-tailed test(Left tailed test)

We have to calculate the p-value.
Degree of freedom = n - 1 = 23
We calculate the p-value from the table corresponding to t score -2.50 and degree of freedom 23.
P-value = 0.009997
0.009997 is the probability of a value being to the left of a number that has a student-t statistic of –2.50.
A rectangular prism has 6 surface.
The answer is 0.8 kilowatts because 4 divided by 5 is 0.8
4/5 - 1/6
= 24/30 - 5/30
= 19/30
The problem you have written
![\sqrt[5]{x^{10}}/2](https://tex.z-dn.net/?f=%5Csqrt%5B5%5D%7Bx%5E%7B10%7D%7D%2F2)
simplifies to

_____
If you intend
![\sqrt[5]{x^{10}/2}](https://tex.z-dn.net/?f=%5Csqrt%5B5%5D%7Bx%5E%7B10%7D%2F2%7D)
then you can multiply by the appropriate fraction to get your first answer choice.
![\displaystyle\sqrt[5]{\frac{x^{10}}{2}}=\frac{\sqrt[5]{x^{10}}}{\sqrt[5]{2}}\cdot\frac{\sqrt[5]{2^4}}{\sqrt[5]{2^4}}\\\\=\frac{x^{2}\sqrt[5]{16}}{\sqrt[5]{2^{5}}}=\bf{\frac{x^{2}\sqrt[5]{16}}{2}}](https://tex.z-dn.net/?f=%5Cdisplaystyle%5Csqrt%5B5%5D%7B%5Cfrac%7Bx%5E%7B10%7D%7D%7B2%7D%7D%3D%5Cfrac%7B%5Csqrt%5B5%5D%7Bx%5E%7B10%7D%7D%7D%7B%5Csqrt%5B5%5D%7B2%7D%7D%5Ccdot%5Cfrac%7B%5Csqrt%5B5%5D%7B2%5E4%7D%7D%7B%5Csqrt%5B5%5D%7B2%5E4%7D%7D%5C%5C%5C%5C%3D%5Cfrac%7Bx%5E%7B2%7D%5Csqrt%5B5%5D%7B16%7D%7D%7B%5Csqrt%5B5%5D%7B2%5E%7B5%7D%7D%7D%3D%5Cbf%7B%5Cfrac%7Bx%5E%7B2%7D%5Csqrt%5B5%5D%7B16%7D%7D%7B2%7D%7D)