When using a one-tailed test and a sample size of 24, what is the probability of a value being to the left of a number that has
1 answer:
Answer:
P-value = 0.009997
Step-by-step explanation:
We are given the following in the question:
Sample size, n = 24
Nature of test: One-tailed test(Left tailed test)
We have to calculate the p-value.
Degree of freedom = n - 1 = 23
We calculate the p-value from the table corresponding to t score -2.50 and degree of freedom 23.
P-value = 0.009997
0.009997 is the probability of a value being to the left of a number that has a student-t statistic of –2.50.
You might be interested in
The difference in gallons per day used is 3.6.
The formula to calculate a z-score is:
,
where X is the value used to calculate the score, μ is the mean and σ is the standard deviation. We have the z-scores so we must work backward:
For both equations, we will cancel the 1.2 by multiplying both sides:
Now we will cancel 2.2 from both equations by adding it to both sides:
3.6+2.2=X-2.2+2.2 and 0+2.2=X-2.2+2.2
5.8=X and 2.2=X
The difference in gas used per day would be given by
5.8-2.2 = 3.6.
The formula to calculate a z-score is:
where X is the value used to calculate the score, μ is the mean and σ is the standard deviation. We have the z-scores so we must work backward:
For both equations, we will cancel the 1.2 by multiplying both sides:
Now we will cancel 2.2 from both equations by adding it to both sides:
3.6+2.2=X-2.2+2.2 and 0+2.2=X-2.2+2.2
5.8=X and 2.2=X
The difference in gas used per day would be given by
5.8-2.2 = 3.6.