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Sergeeva-Olga [200]
3 years ago
5

When using a one-tailed test and a sample size of 24, what is the probability of a value being to the left of a number that has

a student-t statistic of –2.50?
Mathematics
1 answer:
UNO [17]3 years ago
3 0

Answer:

P-value = 0.009997                                                  

Step-by-step explanation:

We are given the following in the question:

Sample size, n = 24

Nature of test: One-tailed test(Left tailed test)

t_{\text{statistic}} = -2.50

We have to calculate the p-value.

Degree of freedom = n - 1 = 23

We calculate the p-value from the table corresponding to t score -2.50 and degree of freedom 23.

P-value = 0.009997

0.009997 is the  probability of a value being to the left of a number that has a student-t statistic of –2.50.

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Simplify -7x - (15y) + 3x - 2y
LUCKY_DIMON [66]

Answer:

Step-by-step explanation:

combine like terms

-7x + 3x - 15y - 2y

-4x - 17y

3 0
3 years ago
Melanie invested $9,800 in an account paying an interest rate of 4.5 compounded quarterly. Amelia invested $9,800 in an account
Zolol [24]

Answer:

$13,082.60 more

Step-by-step explanation:

Melanie:

A=P(1+\frac{r}{n})^(20)\\ A=9800(1+\frac{.045}{4})^(20)\\A=$12,257.36

Amelia:

A=Pe^(rt)\\A=9800e^(.0475*20)\\A=$25,339.95

Amelia-Melanie= $13,082.60

6 0
2 years ago
Can someone help me with this question!Does the shaded region below represent a value of 3/4 why or why not? Please help immedia
Nana76 [90]

Answer:

Yes

Step-by-step explanation:

Because the circle is divided into 4 parts, and 3 out of 4 of the parts are shaded.

5 0
3 years ago
Read 2 more answers
How do you do number 1?<br>Whenever I tried to answer it, I always get fraction. help me.​
Flura [38]

Answer:

The pairs are (13,15) and (-15,-13).

Step-by-step explanation:

If n is an odd integer, the very next odd integer will be n+2.

n+1 is even (so we aren't using this number)

The sum of the squares of (n) and (n+2) is 394.

This means

(n)^2+(n+2)^2=394

n^2+(n+2)(n+2)=394

n^2+n^2+4n+4=394               since (a+b)(a+b)=a^2+2ab+b^2

Combine like terms:

2n^2+4n+4=394

Subtract 394 on both sides:

2n^2+4n-390=0

Divide both sides by 2:

n^2+2n-195=0

Now we need to find two numbers that multiply to be -195 and add up to be 2.

15 and -13 since 15(-13)=-195 and 15+(-13)=2

So the factored form is

(n+15)(n-13)=0

This means we have n+15=0 and n-13=0 to solve.

n+15=0

Subtract 15 on both sides:

n=-15

n-13=0

Add 13 on both sides:

n=13

So if n=13 , then n+2=15.

If n=-15, then n+2=-13.

Let's check both results

(n,n+2)=(13,15)

13^2+15^2=169+225=394.  So (13,15) looks good!

(n,n+2)=(-15,-13)

(-15)^2+(-13)^2=225+169=394.  So (-15,-13) looks good!

6 0
3 years ago
Please help. I am doing a test and I do not understand what I am being asked.
Oksanka [162]

Answer:

one

Step-by-step explanation:

i have no idea what kind of test ur taking my guy but have fun

5 0
3 years ago
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