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qwelly [4]
3 years ago
15

At STP, what volume of container would be needed to hold 3.2 moles of gas?

Chemistry
1 answer:
Rzqust [24]3 years ago
3 0

78.4 L volume of container is required to hold 3.2 moles of gas.

Explanation:

  • STP is defined as the standard temperature and pressure of a gas in room temperature conditions. At STP, one mole of the gas which has Avogadro's number of molecules in it will occupy a volume of 22.4 L.
  • So, one mole of a substance or gas will occupy a volume of 22.4 L then the volume of the container needed for  3.2 moles of gas is calculated by multiplying 22.4 L, standard volume with the moles of the gas 3.2 moles.
  • Hence, the answer would be 78.4 L.
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Draw an ether that contains exactly five carbon atoms and only single bonds
Eddi Din [679]

<em>Answer:</em>

  •                                       H3CH2COCH2CH2CH3

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8 0
3 years ago
Calculate the density of CO2 in g/cm3 at room temperature(25 degrees Celsuis) and pressure(1 atm) assuming it acts as an ideal g
Readme [11.4K]

Answer:

density=1.8x10^{-3}g/mL

Explanation:

Hello,

Considering the ideal equation of state:

PV=nRT

The moles are defined in terms of mass as follows:

n=\frac{m}{M}

Whereas M the gas' molar mass, thus:

PV=\frac{mRT}{M}

Now, since the density is defined as the quotient between the mass and the volume, we get:

P=\frac{m}{V} \frac{RT}{M}

Solving for m/V:

density= m/V=\frac{PM}{RT}

Thus, the result is given by:

density=\frac{(1atm)(44g/mol)}{[0.082atm*L/(mol*K)]*298.15K} \\density=1.8g/L=1.8x10^{-3}g/mL

Best regards.

8 0
3 years ago
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