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qwelly [4]
3 years ago
15

At STP, what volume of container would be needed to hold 3.2 moles of gas?

Chemistry
1 answer:
Rzqust [24]3 years ago
3 0

78.4 L volume of container is required to hold 3.2 moles of gas.

Explanation:

  • STP is defined as the standard temperature and pressure of a gas in room temperature conditions. At STP, one mole of the gas which has Avogadro's number of molecules in it will occupy a volume of 22.4 L.
  • So, one mole of a substance or gas will occupy a volume of 22.4 L then the volume of the container needed for  3.2 moles of gas is calculated by multiplying 22.4 L, standard volume with the moles of the gas 3.2 moles.
  • Hence, the answer would be 78.4 L.
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What should go in the blank?
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Answer:

³⁸₂₀Ca.

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³⁸₁₉K –> __ + ⁰₋₁β

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³⁸₁₉K –> ʸₓA + ⁰₋₁β

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Thus,

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6 0
3 years ago
The carbon-14 content of a wooden harpoon handle found in an Inuit archaeological site was found to be 61.9% of the carbon-14 co
astraxan [27]

Answer:

3,964 years.

Explanation:

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Where, k is the rate constant of the reaction.

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∴ k =0.693/(t1/2) = 0.693/(5,730 years) = 1.21 x 10⁻⁴ year⁻¹.

  • Also, we have the integral law of first order reaction:

<em>kt = ln([A₀]/[A]),</em>

where, k is the rate constant of the reaction (k = 1.21 x 10⁻⁴ year⁻¹).

t is the time of the reaction (t = ??? year).

[A₀] is the initial concentration of the sample ([A₀] = 100%).

[A] is the remaining concentration of the sample ([A] = 61.9%).

∴ t = (1/k) ln([A₀]/[A]) = (1/1.21 x 10⁻⁴ year⁻¹) ln(100%/61.9%) = 3,964 years.

7 0
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