All categories

2 years ago

Draw an ether that contains exactly five carbon atoms and only single bonds

Chemistry

1 answer:

Eddi Din [679]2 years ago

8 0

Answer:

H3CH2COCH2CH2CH3

Ether:

Ether are organic compounds that contain ether functional group , in which oxygen atom is connected with two alkyl or aryl group.

They have general formula as follow

R---O---R or R'---O----R or R'---O---R'

while R = Alkyl

R' = Aryl

You might be interested in

Using complete subshell notation (not abbreviations, 1s 22s 22p 6 , and so forth), predict the electron configuration of each of

dybincka [34]

Answer: The electronic configuration of the elements are written below.

Explanation:

Electronic configuration is defined as the representation of electrons around the nucleus of an atom.

Number of electrons in an atom is determined by the atomic number of that atom.

For the given options:

Option a: Carbon (C)

Carbon is the 6th element of the periodic table. The number of electrons in carbon atom are 6.

The electronic configuration of carbon is $1s^22s^22p^2$

Option b: Phosphorus (P)

Phosphorus is the 15th element of the periodic table. The number of electrons in phosphorus atom are 15.

The electronic configuration of phosphorus is $1s^22s^22p^63s^23p^3$

Option c: Vanadium (V)

Vanadium is the 23rd element of the periodic table. The number of electrons in vanadium atom are 23.

The electronic configuration of vanadium is $1s^22s^22p^63s^23p^64s^23d^3$

Option d: Antimony (Sb)

Antimony is the 51st element of the periodic table. The number of electrons in antimony atom are 51.

The electronic configuration of antimony is $1s^22s^22p^63s^23p^64s^23d^{10}4p^65s^24d^{10}5p^3$

Option e: Samarium (Sm)

Samarium is the 62nd element of the periodic table. The number of electrons in samarium atom are 62.

The electronic configuration of samarium is $1s^22s^22p^63s^23p^64s^23d^{10}4p^65s^24d^{10}5p^66s^24f^6$

Hence, the electronic configuration of the elements are written above.

4 0

3 years ago

Which describes the volume of 1 mol of gas at standard temperature and pressure?

Setler79 [48]

Volume of 1 mol of gas at standard temperature and pressure is 22.4 L.

That is using ideal gas equation:

PV = nRT

P=pressure

V=volume

n=number of moles

R=gas constant

T=temperature

at STP,

P=1 atm

T=273K

n=1(given)

Putting all the values in the equation will give,

V= 22.4 L

So, the answer is :

The volume of 1 mol of gas at standard temperature and pressure is 22.4 L.

3 0

3 years ago

Deep sea divers use a mixture of helium and oxygen to breathe. Assume that a diver is going to a depth of 150 feet where the tot

Svetlanka [38]

Answer:

4.525% is the percentage by volume of oxygen in the gas mixture.

Explanation:

Total pressure of the mixture = p = 4.42 atm

Partial pressure of the oxygen = $p_1=0.20 atm$

Partial pressure of the helium = $p_2$

$p_1=p\times \chi_1$ (Dalton law of partial pressure)

$0.20 atm=4.42 atm\times \chi_1$

$\chi_1=\frac{0.20 atm}{4.42 atm}=0.04525$

$\chi_2=1-\chi_1=1-0.04525=0.95475$

$chi_1+chi_2=1$

$n_1=0.04525 mol,n_2=0.95475 mol$

According Avogadro law:

$Moles\propto Volume$ (At temperature and pressure)

Volume occupied by oxygen gas = $V_1$

Total moles of gases = n = 1 mol

Total Volume of the gases = V

$\frac{n_1}{V_1}=\frac{n}{V}$

$\frac{V_1}{V}=\frac{n_1}{n}=\frac{0.04525 mol}{1 mol}$

Percent by volume of oxygen in the gas mixture:

$\frac{V_1}{V}\times 100=\frac{0.04525 mol}{1 mol}\times 100=4.525\%$

6 0

3 years ago

Which of the following would dissolve in water, and why?

Oduvanchick [21]

Answer:

It should be acetic acid.

Explanation:

When you have ionic bonds, the ionic bonds will always be water soluble; the polarity doesn't matter for this case.

4 0

3 years ago

1.00 L of gas at a standard temperature and pressure is compressed to 473mL. What is the new pressure of the gas?

Nadusha1986 [10]

Answer:

The pressure of the gas is 2.11 atm.

Explanation:

From the given,

$V_{1}=1.00\,L$

$P_{1}=1\,atm$

$P_{2}=?$

$V_{2}=473\,ml=0.473\,L$

$P_{1}V_{1}=P_{2}V_{2}$

$(1)(1)=(0.473)(P_{2})$

$P_{2}=\frac{(1)(1)}{0.473}=2.11$

Therefore, The pressure of the gas is 2.11 atm.

6 0

3 years ago