2 years ago

Helppp mehhh thanks:))

Chemistry

1 answer:

Scorpion4ik [409]2 years ago

3 0

Answer:

natural gas

Explanation:

your welcomeee

You might be interested in

23.It is possible to dilute a solution by...Select one:a. adding more solute to the solution.b. adding more solvent to the solut

joja [24]

To dilute a solute in a solution, it is necessary to add a proper solvent for the reaction to occur, and adding more solvent will cause the solution to dilute even more, therefore the best answer will be letter B

7 0

8 months ago

I need help plz this is driving me crazy

Elis [28]

A= 6
B= 2
C= 1
D= 5
E= 3
F= 4

4 0

2 years ago

We gave an object with a density of 620 g/cm^3 and a volume of 75cm^3. What is the mass of this object?

Hitman42 [59]

$d=\frac{m}{V} \ \ \ \Rightarrow \ \ m=dV\\\\
d=620\frac{g}{cm^{3}}\\
V=75cm^{3}\\\\\
m=620\frac{g}{cm^{3}}*75cm^{3}=46500g$

6 0

2 years ago

How does the concentration of a gas in solution change when the partial pressure of the gas above the solution increases?

irakobra [83]

Because the concentration of molecules in the gas phase increases with increasing pressure, the concentration of dissolved gas molecules in the solution at equilibrium is also higher at higher pressures

5 0

1 year ago

Question 8 of 8> 0 Attempt 2 A chemist needs to determine the concentration of a sulfuric acid solution by titration with a s

Nesterboy [21]

Answer:

12.29 M

Explanation:

The reaction that takes place is:

H₂SO₄ + 2NaOH → 2Na⁺ + SO₄⁻² + 2H₂O

Now let's calculate the moles of H₂SO₄ that were titrated:

$0.1284 M * 0.1915L*\frac{1molAcid}{2molNaOH}$ = 0.01229 mol H₂SO₄.

Thus, the concentration of the diluted solution is:

0.01229 mol H₂SO₄ / 0.010 L = 1.229 M

Finally, the concentration of the original acid solution is:

$1.229 M*\frac{250mL}{25mL}$ = 12.29 M

5 0

2 years ago