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mel-nik [20]
3 years ago
15

Which of the following solutions will have the lowest boiling point?

Chemistry
1 answer:
Arada [10]3 years ago
5 0
Boiling point of
glucose = 150°C
AlCl3 = 180°C
NaCl = 1,413°C
CaCl2 = 1,935°C

Therefore, the one with the lowest boililng point is glucose
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Save the ________ used to extract metals.
MrRa [10]

Answer:

Save the *minerals* used to extract metals.

6 0
2 years ago
Design a test to determine whether thorium-234 also emits particles. First, explain how Rutherford’s experiment measured positiv
liubo4ka [24]

The characteristics of the α and β particles allow to find  the design of an experiment to measure the ²³⁴Th particles is:

  • On a screen, measure the emission as a function of distance and when the value reaches a constant, there is the beta particle emission from ²³⁴Th.
  • The neutrons cannot be detected in this experiment because they have no electrical charge.

In Rutherford's experiment, the positive particles directed to the gold film were measured on a phosphorescent screen that with each arriving particle a luminous point is seen.

The particles in this experiment are α particles that have two positive charge and two no charged is a helium nucleus.

The test that can be carried out is to place a small ours of Thorium in front of a phosphorescent screen and see if it has flashes, with the amount of them we can determine the amount of particle emitted per unit of time.

Thorium has several isotopes, with different rates and types of emission:

  • ²³²Th emits α particles, it is the most abundant 99.9%
  • ²³⁴Th emits β particles, exists in small traces.

In this case they indicate that the material used is ²³⁴Th, which emits β particles that are electrons, the detection of these particles is more difficult since it has one negative charge, it has much lower mass, but they can travel further than the particles α, therefore, for what type of isotope we have, we can start measuring at a small distance and increase the distance until the reading is constant. At this point all the particles that arrive are β, which correspond to ²³⁴Th.

Neutron detection is much more difficult since these particles have no charge and therefore do not interact with electrons and no flashing on the screen is varied.

In conclusion with the characteristics of the α and β particles we can find the design of an experiment to measure the ²³⁴Th particles is:

  • On a screen, measure the emission as a function of distance and when the value reaches a constant, there is the β particle emission from ²³⁴Th.
  • The neutrons cannot be detected in this experiment because they have no electrical charge.

Learn more about radioactive emission here: brainly.com/question/15176980

7 0
2 years ago
What is the relationship between mole, Avogadro number and mass?
weeeeeb [17]

Answer:

The mass of one mole of a substance is equal to that substance's molecular weight. ... water is 18.015 atomic mass units (amu), so one mole of water weight 18.015 grams. ... Avogadro's number is a proportion that relates molar mass on an atomic ... one molecule of water (H2O), one mole of oxygen (6.022×1023 of O atoms)

5 0
2 years ago
The production of ammonia (NH3) under standard conditions at 25°C is represented by the following thermochemical equation. N2(g)
asambeis [7]

Answer:

44,901 kilo Joule heat is released when 1.663\times 10^4 g grams of ammonia is produced.

Explanation:

Moles of ammonia  gas produced :

\frac{1.663\times 10^4 g}{17 g/mol}=978.235 mol

According to reaction, when 2 moles of ammonia are produced 9.18 kilo joules of energy is also released.

So, When 978.235 moles of ammonia gas is produced the energy released will be:

\frac{-91.8 kJ}{2}\times 978.235 mol=-44,900.98 kJ\approx -44,901 kJ

(negative sign indicates that energy is released as heat)

44,901 kilo Joule heat is released when 1.663\times 10^4 g grams of ammonia is produced.

7 0
3 years ago
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