All categories

4 years ago

Please help! 10 points!!

Chemistry

2 answers:

klemol [59]4 years ago

8 0

Hi,
The answer is HF since hydrogen bonds are can be formed only between Hydrogen and Fluorine, Oxygen or Nitrogen.

12345 [234]4 years ago

5 0

Both H-F and CH₃CH₂CH₂CH₂O-H have the potential to form hydrogen bonds.

Molecules with O-H, N-H, and F-H covalent bonds can form hydrogen bonds.

You might be interested in

What is the answer??????

balandron [24]

Answer:

Digestion of food.

Explanation:

I hope my answer help you.

5 0

3 years ago

Read 2 more answers

Why Group 18 elements on the periodic table rarely form compounds

lawyer [7]

Most elements on group 18 are the Noble Gases. They already have a complete last level with 8 electrones. Actually they can form compounds but only on the lab and they will not even last half a second.

4 0

3 years ago

Lucia wants to develop a process for dyeing shirts so that the color will not fade when the shirt is washed. She proceeds with t

Firlakuza [10]

I cant because it not full

3 0

4 years ago

Read 2 more answers

A 720. cm^3 vessel contains a mixture of Ar and Xe. If the mass of the gas mixture is 2.966 g at 25.0°C and the pressure is 760.

sleet_krkn [62]

Explanation:

The given data is as follows.

Pressure (P) = 760 torr = 1 atm

Volume (V) = $720 cm^{3}$ = 0.720 L

Temperature (T) = $25^{o}C$ = (25 + 273) K = 298 K

Using ideal gas equation, we will calculate the number of moles as follows.

PV = nRT

Total atoms present (n) = $\frac{PV}{RT}$

= $1 \times \frac{0.720 L}{0.0821 \times 298}$

= 0.0294 mol

Let us assume that there are x mol of Ar and y mol of Xe.

Hence, total number of moles will be as follows.

x + y = 0.0294

Also, 40x + 131y = 2.966

x = 0.0097 mol

y = (0.0294 - 0.0097)

= 0.0197 mol

Therefore, mole fraction will be calculated as follows.

Mol fraction of Xe = $\frac{y}{(x+y)}$

= $\frac{0.0197}{0.0294}$

= 0.67

Therefore, the mole fraction of Xe is 0.67.

6 0

3 years ago

If a gas is moved from a large container to a small container but its temperature and number of moles remain the same, what woul

bazaltina [42]

To solve this we assume that the gas is an ideal gas. Then, we can use the ideal gas equation which is expressed as PV = nRT. At a constant temperature and number of moles of the gas the product of PV is equal to some constant. At another set of condition of temperature, the constant is still the same. Calculations are as follows:

P1V1 =P2V2

P2 = P1V1/V2

The correct answer is the first option. Pressure would increase. This can be seen from the equation above where V2 is indirectly proportional to P2.

8 0

3 years ago

Read 2 more answers