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Flauer [41]
3 years ago
5

How does the highly reactive nature chlorine contribute to the creation of ozone holes in the upper atmosphere?

Chemistry
1 answer:
liberstina [14]3 years ago
6 0
Chlorine is a halogen and is very reactive and unstable. If released in an elemental form (Cl2), it would react with other substances immediately. However, <span>chlorofluorocarbons (CFCs) which contain chlorine are unreactive and when released they eventually end up in the upper atmosphere still "intact". In the upper atmosphere, sunlight is more intense and is able to break apart CFC, releasing the highly reactive chlorine which in turns destroys ozone which is more abundant in the upper atmosphere (stratosphere). </span>
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A- south<br> B- north <br> C-west<br> D- east <br> Help ASAP no links or I’m reporting
Agata [3.3K]

Answer:

east

Explanation:

5 0
3 years ago
Balance the following reaction. A coefficient of "1" is understood. Choose option "blank" for the correct answer if the
Vera_Pavlovna [14]

2NH₂ + O₂ → N₂ + 2H₂O

<u>Explanation:</u>

Balancing the equation means, the number of atoms on both sides of the equation must be the same.

In the case of the given equation, we have to find out whether it is balanced or not.

2NH₂ + O₂ →  N₂ + 2H₂O

Atoms       Number of atoms before balancing     after balancing

                 LHS                 RHS                                    LHS         RHS

N               1                        2                                            2              2

H               2                       2                                            4              4                        

O               2                       1                                            2                2

To balance the N atoms, we have to put 2 in front of NH₂, and then to balance the H, O atoms, we have to put 2 in front of H₂O, so that each atom in left hand as well as right hand side of the equation was balanced.

8 0
3 years ago
According to this balanced equation, how many grams of water (H.0) form in
miskamm [114]

Answer:

your simpal answer is 177.32

8 0
3 years ago
Read 2 more answers
How many photons are produced in a laser pulse of 0.497 J at 469 nm?
dimulka [17.4K]
<span>E=hν</span> where E is the energy of a single photon, and ν is the frequency of a single photon. We recall that a photon traveling at the speed of light c and a frequency ν will have a wavelength λ given by <span>λ=<span>cν</span></span>λ will have an energy given by <span>E=<span><span>hc</span>λ</span></span><span>λ=657</span> nm. This will be <span>E=<span><span>(6.626×<span>10<span>−34</span></span>)(2.998×<span>108</span>)</span><span>(657×<span>10<span>−9</span></span>)</span></span>=3.0235×<span>10<span>−19</span></span>J</span> So we now know the energy of one photon of wavelength 657 nm. To find out how many photons are in a laser pulse of 0.363 Joules, we simply divide the pulse energy by the photon energy or <span>N=<span><span>E<span>pulse </span></span><span>E<span>photon</span></span></span>=<span>0.363<span>3.0235×<span>10<span>−19</span></span></span></span>=1.2×<span>1018</span></span>So there would be <span>1.2×<span>1018</span></span><span> photons of wavelength 657 nm in a pulse of laser light of energy 0.363 Joules.</span>
7 0
3 years ago
Read 2 more answers
What is the Molar Mass of Cs2SO3?​
Airida [17]

Answer:

345.89 g/mol

Explanation:

To find the molar mass, find the atomic mass of all the elements from a periodic table.

Cs - 132.91 × 2 = 265.82

S - 32.07

O - 16.00 × 3 = 48.00

Now add them all together.

265.82 + 32.07 + 48.00 = 345.89 g/mol

Hope that helps.

8 0
3 years ago
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