What are the options the your question
Answer:
0.0922 M
Explanation:
The problem first states that the titration is made using NaOH, and later asks about the addition of KOH. I'm going to assume NaOH was used throughout the whole problem. The result does not change if it was KOH instead.
The reaction that takes place is:
- HClO₄ + NaOH → NaClO₄ + H₂O
First we <u>calculate how many HClO₄ moles are there in the sample</u>, using the <em>given molarity and volume</em>:
- 0.624 M * 13.0 mL = 8.11 mmol HClO₄
Then we <u>calculate how many NaOH moles were added</u>:
- 0.258 M * 15.0 mL = 3.87 mmol NaOH
Now we calculate how many HClO₄ remained after the reaction:
- 8.11 - 3.87 = 4.24 mmol HClO₄
As <em>HClO₄ is a strong acid</em>, 4.24 mmol HClO₄ = 4.24 mmol H⁺
Finally we <u>calculate the molarity of H⁺</u>, using the<em> calculated number of moles and final volume</em>:
- Final volume = 31.0 mL + 15.0 mL = 46.0 mL
- 4.24 mmol / 46.0 mL = 0.0922 M
The new substances that result from a chemical reaction is called product
Answer:
Is there a picture or smth?
Explanation:
Answer:
A supposition or proposed explanation made on the basis of limited evidence as a starting point for further investigation.
Explanation:
^^
