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Flauer [41]
3 years ago
5

How does the highly reactive nature chlorine contribute to the creation of ozone holes in the upper atmosphere?

Chemistry
1 answer:
liberstina [14]3 years ago
6 0
Chlorine is a halogen and is very reactive and unstable. If released in an elemental form (Cl2), it would react with other substances immediately. However, <span>chlorofluorocarbons (CFCs) which contain chlorine are unreactive and when released they eventually end up in the upper atmosphere still "intact". In the upper atmosphere, sunlight is more intense and is able to break apart CFC, releasing the highly reactive chlorine which in turns destroys ozone which is more abundant in the upper atmosphere (stratosphere). </span>
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1. 32.5grams of NaOH (sodium hydroxide) reacts an excess of CO2 (carbon dioxide).
SOVA2 [1]

a. 43.1 g

b. 38.2%

<h3>Further explanation</h3>

Given

32.5 grams of NaOH

Required

The theoretical yield of Na₂CO₃

The percent yield

Solution

Reaction

2NaOH(s) + CO₂(g) → Na₂CO₃(s) + H₂O(l)

mol NaOH :

= mass : MW

= 32.5 : 40 g/mol

= 0.8125

mol Na₂CO₃ from the equation :

= 1/2 x mol NaOH

= 1/2 x 0.8125

= 0.40625

a.

Mass Na₂CO₃ :

= mol x MW Na₂CO₃

= 0.40625 x 106 g/mol

= 43.0625≈43.1 g

b. % yield = (actual/theoretical) x 100%

%yield = 16.45/43.1 x 1005

%yield = 38.17%≈38.2%

5 0
3 years ago
Can someone pls help :/
jeka57 [31]

Answer:

option C. Addition of protons to the atomic nucleus.

Explanation:

Elements are fundamentally made up of atoms. Atoms in turn has three sub particles.

These particles are; neutrons, electrons and protons.

The sub particles responsible for the mass of an atoms is basically the protons and neutrons. Going through the options;

The correct option is option C. Addition of protons to the atomic nucleus.

6 0
3 years ago
An unknown acid solution has PH 3.4. 66% of the acid is ionized. Whats the pka?
juin [17]

Answer:

pKa=3.58

Explanation:

Hello,

In this case, since the pH defines the concentration of hydrogen:

pH=-log([H^+])

[H^+]=10^{-pH}=10^{-3.4}=3.98x10^{-4}

And the percent ionization is:

\% \ ionization=\frac{[H^+]}{[HA]}*100\%

We compute the concentration of the acid, HA:

[HA]=\frac{[H^+]}{\% \ ionization}*100\%=\frac{3.98x10^{-4}}{66\%}  *100\%\\\\

[HA]=6.03x10^{-4}

Thus, the Ka is:

Ka=\frac{[H^+][A^-]}{[HA]}=\frac{3.98x10^{-4}*3.98x10^{-4}}{6.03x10^{-4}}\\  \\Ka=2.63x10^{-4}

So the pKa is:

pKa=-log(Ka)=-log(2.63x10^{-4})\\\\pKa=3.58

Regards.

5 0
3 years ago
Earth's Revolution question:
Murljashka [212]

Answer:

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7 0
3 years ago
What is the minimum amount of heat required to completely melt 20.0 grams of ice af it's melting point
Veseljchak [2.6K]
The answer is 6608J ..
8 0
3 years ago
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