Answer:
118.776 mmHg
Explanation:
The equation of the reaction is;
C4H10(g) + 13/2 O2(g) ------> 4CO2(g) + 5H20(g)
Now the mole ratio according to the balanced reaction equation is;
1 : 6.5 : 4 : 5
Hence, the total number of moles present = 1 + 6.5 + 4 + 5 = 16.5 moles
Mole fraction of water vapour = 5/16.5 = 0.303
We also know that;
Partial pressure= mole fraction * total pressure
Partial pressure of H20(g) = 0.303 * 392 mmHg = 118.776 mmHg
Answer:
Two moles of HC2H3O2 react with one mole of Ca(OH)2 to produce one mole of calcium acetate and two moles of water.
Explanation:
HC2H3O2 is Acetic acid that can also be represented as (CH3COOH).
when Ca(OH)2 reacts with Acetic acid the product formed will be Calcium acetate and water
Chemically the reaction can be represented as
2CH
3
COOH + Ca(OH)
2 → Ca(CH
3
COO)
2 + 2H
2
O
Two moles of CH3COOH react with one mole of Ca(OH)2 to produce one mole of Ca(CH3COO)2 and two moles of H2O.
You can tell if each side of the equation has the same molar mass.
When comparing single bonds between atoms of comparable types, the stronger the bond is, the bigger the atom, the weaker it is.
The length of the X-H bond lengthens while the strength of the bond shortens with increasing halogen size (F-H strongest, I-H weakest). When comparing single bonds between atoms of similar sorts, the larger the atom, the weaker the bond. It can be explained by the fact that less energy is required to break the bond the bigger the atom's atomic size. The force of attraction from the nucleus to the outermost orbit will be less for iodine since it has a larger atom than the other elements in the group.
Learn more about single bonds here-
brainly.com/question/16626126
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Answer:
0.683 moles of the gas are required
Explanation:
Avogadro's law relates the moles of a gas with its volume. The volume of a gas is directely proportional to its moles when temperature and pressure of the gas remains constant. The law is:
V₁n₂ = V₂n₁
<em>Where V is volume and n are moles of 1, initial state and 2, final state of the gas.</em>
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Computing the values of the problem:
1.50Ln₂ = 5L*0.205mol
n₂ = 0.683 moles of the gas are required
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