Answer:
Aerobic Respiration
It can be found in the cytoplasm and the mitochondria.
Glucose breaks down into carbon dioxide and water.
Anaerobic Respiration
It can be found only in the cytoplasmic.
Glucose breaks down into ethyl alcohol, carbon dioxide and energy
Answer:
Its single - displacement.
Explanation:
Answer:
Velocity, u = 14.7 m/s
Explanation:
It is given that, a driver can probably survive an acceleration of 50 g that lasts for less than 30 ms, but in a crash with a 50 g acceleration lasting longer than 30 ms, a driver is unlikely to survive.
Let v is the highest speed that the car could have had such that the driver survived. Using a = -50 g and t = 30 ms
Using first equation of kinematics as :
In case of crash the final speed of the driver is, v = 0
u = 14.7 m/s
So, the highest speed that the car could have had such that the driver survived is 14.7 m/s. Hence, this is the required solution.
Answer:
-1.5 N because 1.5 N would be upwards and -1.5 N would be downwards
Neon = app. 20.1795 g/mol
<span>Bromine = app. 79.904 g/mol </span>
<span>-----> 79.904 g/mol / 20.1795 g/mol = 3.96 (Close to 4) </span>
<span>Using Moles In 1000 g </span>
<span>1000 g / 20.1795 g/mol = app. 49.555 mol of Ne </span>
<span>1000 g / 79.904 g/mol = app. 12.515 mol of Br </span>
<span>-----> 49.555 mol / 12.515 mol = 3.96 (Close to 4) </span>
<span>Using Avogadro's Number </span>
<span>49.555 mol x 6.022x10^23 atoms = app. 2.984x10^25 atoms of Ne </span>
<span>12.515 mol x 6.022x10^23 atoms = app. 7.537x10^24 atoms of Br </span>
<span>-----> 2.984x10^25 / 7.537x10^24 = 3.96 (Close to 4) </span>
<span>So no matter how you look at it or calculate it, the answer is always the same. </span>
<span>I hope it helps!</span>
