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VikaD [51]
2 years ago
6

What characteristic frequencies in the infrared spectrum of your sodium borohydride reduction product will you look for to deter

mine whether the carbonyl group (in ethyl vanillin) has been converted to an alcohol functional group? That is, if the transformation has occurred, which characteristic frequencies should be present in the infrared spectrum, and which should be absent? How would the infrared spectrum for the sodium borohydride reduction product be affected if the product were still wet with water? Explain your reasoning.
Chemistry
1 answer:
kkurt [141]2 years ago
5 0

Answer:

A)The characteristic frequency to look out for is  1720-1740 cm-1 (for C=O) for which will disappear in the end product but initially present in the reactant.

B)Characteristic frequency  present in the infrared spectrum will be at a peak of  3300-3400 cm-1 which will be due to O-H stretch.

C)If the product is wet with water there will be no change in the infrared spectrum

Explanation:

The characteristic frequency to look out for is  1720-1740 cm-1 (for C=O) for which will disappear in the end product but initially present in the reactant.

Characteristic frequency  present in the infrared spectrum will be at a peak of 3300-3400 cm-1 which will be due to O-H stretch.

If the product is wet with water there will be no change in the infrared spectrum

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Vladimir [108]

Answer: The reaction is exothermic reaction as the energy of products is less than the energy of reactants.

Explanation: Exothermic reactions are defined as the reactions in which energy of the product is less than the energy of the reactants. The total energy is released in the form of heat and \Delta H for the reaction comes out to be negative.

Labeling of the parts in the diagram:

A represents the activation energy which is the energy required by reactants to cross the energy barrier to get converted to products.

E represents the potential energy of the reactants.

B represents the activated complex.

D represents the potential energy of the products.

C represents the total enthalpy change of the reaction, which comes out to be negative for exothermic reactions.

\Delta H=E_P-E_R

7 0
2 years ago
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20.352 mL of chlorine under a pressure of 680. mm Hg are
Lunna [17]

Answer:

0.01144L or 1.144x10^-2L

Explanation:

Data obtained from the question include:

V1 (initial volume) = 20.352 mL

P1 (initial pressure) = 680mmHg

P2 (final pressure) = 1210mmHg

V2 (final volume) =.?

Using the Boyle's law equation P1V1 = P2V2, the volume of the container can be obtained as follow:

P1V1 = P2V2

680 x 20.352 = 1210 x V2

Divide both side by 1210

V2 = (680 x 20.352)/1210

V2 = 11.44mL

Now we need to convert 11.44mL to L in order to obtain the desired result. This is illustrated below:

1000mL = 1 L

11.44mL = 11.44/1000 = 0.01144L

Therefore the volume of the container is 0.01144L or 1.144x10^-2L

7 0
2 years ago
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Listed following are some distinguishing characteristics of comets, meteors, and asteroids. Match these to the appropriate categ
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The distinguishing characteristics of comets, meteors, and asteroids are its composition.

<h3>What are the characteristics of comets, meteors and asteroids?</h3>

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So we can conclude that the distinguishing characteristics of comets, meteors, and asteroids are its composition.

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2 years ago
Nitrogen and hydrogen combine at a high temperature, in the presence of a catalyst, to produce ammonia. N 2 ( g ) + 3 H 2 ( g )
Kisachek [45]

Answer:

After complete reaction, 0.280 moles of ammonia are produced

Explanation:

Step 1: Data given

Number of moles N2 = 0.140 moles

Number of moles H2 = 0.434 moles

Step 2: The balanced equation

N2(g) + 3H2 (g) ⟶ 2NH3 (g)

Step 3: Calculate the limiting reactant

For 1 mol N2 we need 3 moles H2 to produce 2 moles NH3

N2 is the limiting reactant. It will completely be consumed (0.140 moles).

H2 is in excess. There will react 3*0.140 = 0.420 moles

There will remain 0.434 - 0.420 = 0.014 moles

Step 4: Calculate moles NH3

For 0.140 moles N2 we'll have 2*0.140 = 0.280 moles NH3

After complete reaction, 0.280 moles of ammonia are produced

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MAXImum [283]
<span>(1) CH3CHCHCH3.................</span>
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3 years ago
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