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VikaD [51]
3 years ago
6

What characteristic frequencies in the infrared spectrum of your sodium borohydride reduction product will you look for to deter

mine whether the carbonyl group (in ethyl vanillin) has been converted to an alcohol functional group? That is, if the transformation has occurred, which characteristic frequencies should be present in the infrared spectrum, and which should be absent? How would the infrared spectrum for the sodium borohydride reduction product be affected if the product were still wet with water? Explain your reasoning.
Chemistry
1 answer:
kkurt [141]3 years ago
5 0

Answer:

A)The characteristic frequency to look out for is  1720-1740 cm-1 (for C=O) for which will disappear in the end product but initially present in the reactant.

B)Characteristic frequency  present in the infrared spectrum will be at a peak of  3300-3400 cm-1 which will be due to O-H stretch.

C)If the product is wet with water there will be no change in the infrared spectrum

Explanation:

The characteristic frequency to look out for is  1720-1740 cm-1 (for C=O) for which will disappear in the end product but initially present in the reactant.

Characteristic frequency  present in the infrared spectrum will be at a peak of 3300-3400 cm-1 which will be due to O-H stretch.

If the product is wet with water there will be no change in the infrared spectrum

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4 years ago
What is the chemical formula for a compound between Li and Br?
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LiBr.

<h3>Explanation</h3>

Note that the group number in this answer refers to the new IUPAC group number, which ranges from 1 to 18. Counts from the left. Start with the first two column (group 1 and 2), go on to the transition elements (Sc, Ti, etc. in group 3 through 12), and continue with the nonmetals (group 13 through 18).  

Li is a group 1 metal. As a metal, it tends to form positive ions ("cations"). Metals in group 1 and 2 are <em>main group</em> metals. The charge on main group metal ions tends to be the same as the group number of the metal. Li is in group 1. The charge on an Li ion will be +1. Formula of the Li ion will be \text{Li}^{+}.

Br is a group 17 nonmetal. As a nonmetal, it tends to form negative ions ("anions"). The charge on nonmetal ions excepting for H tends to equal the group number of the nonmetal minus 18. Br is in group 17. The charge on a Br ion will be 17 - 18 = -1. Formula of the Br ion will be \text{Br}^{-}

All the ions in an ionic compound carry charge. However, some of the ions like \text{Li}^+ are positive. Others ions like \text{Br}^{-} are negative. Charge on the two types of ions balance each other. As a result, the compound is <em>overall</em> neutral.

1 × (+1) + 1 × (-1) = 0. The positive charge on one \text{Li}^{+} ion balances the negative charge on one \text{Br}^{-} ion. The two ions would pair up at a 1:1 ratio.

The empirical formula for an ionic compound shows all the ions in the compound. Positive ions are written in front of negative ions. \text{Li}^{+} is positive and \text{Br}^{-} is negative. The formula shall also show the simplest ratio between the ions. For the compound between Li and Br, a 1:1 ratio will be the simplest. The "1" subscript in an empirical formula can be omitted. Hence the formula: LiBr.

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3 years ago
The solubility of a compound with a molecular weight of 233.2 is determined to be 27.9 g in 125.0 g of water at 398 K. Express t
sp2606 [1]

Answer:

0.960 m

Explanation:

Given data

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First, we will calculate the moles of solute.

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The molality of the compound is:

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