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3 years ago

How much water does the average person in the U.S. use on a daily basis?

Chemistry

2 answers:

choli [55]3 years ago

5 0

Answer: The average person drinks 8 cups per day, equaling to 1/2 gallon per day and 182.5 gallons per year.

Explanation:

melomori [17]3 years ago

3 0

Answer:

An average of 82 gallons of water a day at home

Explanation:

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What is the percent error for the experiment if the actual density is

OLga [1]

Answer:

<h3>The answer is 40.96%</h3>

Explanation:

The percentage error of a certain measurement can be found by using the formula

$P(\%) = \frac{error}{actual \: \: number} \times 100\% \\$

From the question

actual density = 2.49g/mL

error = 2.49 - 1.47 = 1.02

We have

$p(\%) = \frac{1.02}{2.49} \times 100 \\ = 40.96385542...$

We have the final answer as

Hope this helps you

4 0

3 years ago

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HELP ASAP PLEASE!!!! 15 PTS!!

Bond [772]

ADD THEM all, and then divide by four. Thats what I would do!

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3 years ago

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Wuy Piolcululugu<br> Give the names of two organs in the chest.<br> 1. ...............<br> 2 m

Arada [10]

Answer:

The organs present inside the chest are :

1. The lungs

2. The heart

Explanation:

The chest cavity is also called as the thoracic cavity. It is the second largest hollow space of the body.In the bottom , it is enclosed by the diaphragm.

This cavity actually contain three space each round with mesothelium , pleural cavity and precardial cavity.

This contain the lungs , the tracheobronchial tree , the heart , the blood vessels which transport the blood between the heart and the lungs.

It also contain the esophagus .

Esophagus is the path through which the food passes from the mouth to the stomach.

8 0

3 years ago

The pH of a 0.65M solution of hydrofluoric acid HF is measured to be 1.68. Calculate the acid dissociation constant Ka of hydrof

sergey [27]

Answer:

Kₐ = 6.7 x 10⁻⁴

Explanation:

First lets write the equilibrium expression, Ka , for the dissociation of hydrofluoric acid:

HF + H₂O ⇄ H₃O⁺ + F⁻

Kₐ = [ H₃O⁺ ] [ F⁻ ] /[ [ HF ]

Since we are given the pH we can calculate the [ H₃O⁺ ] ( pH = - log [ H₃O⁺ ] , and because the acid dissociates into a 1: 1 relation , we will also have [F⁻ ]. The [ HF ] is given in the question so we have all the information that is needed to compute Kₐ.

pH = -log [ H₃O⁺ ]

1.68 = - log [ H₃O⁺ ]

Taking antilog to both sides of this equation:

10^-1.68 = [ H₃O⁺ ] ⇒ 2.1 X 10⁻² M= [ H₃O⁺ ]

[ F⁻ ] = 2.1 X 10⁻² M

Solving for Kₐ :

Kₐ = ( 2.1 X 10⁻² ) x ( 2.1 X 10⁻² ) / 0.65 = 6.7 x 10⁻⁴

(Rounded to two significant figures, the powers of 10 have infinite precision )

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3 years ago

(4 points) The following lead compound for a pharmaceutical drug contains a rotatable bond. Using the principles of rigidificati

masya89 [10]

Answer:

Explanation:

The solution has been attached

3 0

2 years ago