Answer:
Plot -11 on the tick mark directly to the left of -10.
Step-by-step explanation:
Hope this helps!
-Josh
Answer:
Ok, as i understand it:
for a point P = (x, y)
The values of x and y can be randomly chosen from the set {1, 2, ..., 10}
We want to find the probability that the point P lies on the second quadrant:
First, what type of points are located in the second quadrant?
We should have a value negative for x, and positive for y.
But in our set; {1, 2, ..., 10}, we have only positive values.
So x can not be negative, this means that the point can never be on the second quadrant.
So the probability is 0.
Answer:
150
Step-by-step explanation:
add three x plus 30 get 30 then add 6y plus 120 and get 120 add them and get 150
Answer:
1. 2(x+3)
2.x-3
3.2(x-3)
4.2-3x
5.x2+3
6.3-2
7.3+2
8.3x-2
9.3/x
10.x/3
Step-by-step explanation:
