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GaryK [48]
3 years ago
8

If f(x) = 6x – 1 and g (x) = StartFraction x + 1 Over 6 EndFraction, which expressions can be used to verify g(x) is the inverse

of f(x)? Check all that apply. 6(6x – 1) – 1 StartFraction (6 x minus 1) + 1 Over 6 EndFraction 6 (StartFraction x + 1 Over 6 EndFraction) minus 1 StartStartFraction (StartFraction x + 1 Over 6 EndFraction) + 1 OverOver 6 EndEndFraction StartFraction x + 1 Over 6 EndFraction + 6 x minus 1
Mathematics
2 answers:
tigry1 [53]3 years ago
5 0

Answer:

(6 x - 1) + 1 over 6   &

6 ( x + 1 Over 6 ) - 1

Step-by-step explanation:

Edge2020

Semmy [17]3 years ago
3 0

Answer:

B. (6 x - 1) + 1 over 6

And

C. 6 ( x + 1 Over 6 ) - 1

Step-by-step explanation:

Just did on edge.

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Explanation:

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Convert the following repeating decimal to a fraction in simplest form .31 with the 1 repeating
bekas [8.4K]

Answer:

14/45

Step-by-step explanation:

So we have the fraction:

0.3\bar1=0.31111...

We can do this algebraically. Follow to following steps:

Let's let this number equal to n. Thus:

0.31111...=n

Since there is only 1 digit repeating, let's multiply everything by 10. So:

3.1111...=10n

Now, subtract n from both sides:

3.1111-n=10n-n

On the left, substitute the number for n. On the right, combine like terms:

3.1111...-0.31111...=9n

All of the 1s will cancel. So:

3.1-0.3=9n

Subtract:

2.8=9n

Divide both sides by 9:

n=2.8/9

Remove the decimal by multiplying both sides by 10:

n=28/90

Reduce:

n=14/45

And we're done!

Use a calculator to check:

14/45\stackrel{\checkmark}{=}0.31111...

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