Step-by-step explanation:
(x^4)^3=(x^3)^4 , true
=> x^(4×3) = x^(3×4) = x^12
13^4 x 13^7= (13^4)^7, false
13^(4+7) = 13^11
(13^4)^7 = 13^(4×7) = 13^28
y^5 x y^0/y^3=(y^2)^1 , true
y^5 x y^0/y^3 = y^(5+0-3) = y^2
(y^2)^1 = y^(2×1) = y^2
q^0 x q^5/q^2=(q^3)^2/q^3, true
q^0 x q^5/q^2= q^(0+5-2)= q^3
(q^3)^2/q^3 = q^(3×2-3) = q^3
Answer:
(-5,1) would be the coordinates of its image
A quadrilateral has 4 vertices and the sum of the measures of the interior angles is 360 degrees. There cannot be 4 diagonals in a quadrilateral.
The equation to solve would be setting
60×- the m plus 75,the b set to 200 the maximum that's wanted to be used. the equation will look like this
200=60x+75
-75. -75
125=60x
125/60 60x/60
2.08=x
and since you cant round the time the answer will be left at 2
The slop would be 1/6.
you put it into slope intercept form (y=mx+b). parallel lines always have the same slope.
