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AysviL [449]
3 years ago
12

ASAP !!

Mathematics
1 answer:
brilliants [131]3 years ago
8 0

Answer:

17

Step-by-step explanation:

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Can someone answer i put brainliest and 13 points
Arturiano [62]

Answer:

Well the first digit of the quotient for 6,139 / by 153 can go in between 1 and 3

Step-by-step explanation:

I hope this helps now have a good and blessed day

3 0
3 years ago
A research firm tests the miles-per-gallon characteristics of three brands of gasoline. Because of different gasoline performanc
Anni [7]

Answer:

A.) At α = 0.05, is there a significant difference in the mean miles-per-gallon characteristics of the three brands of gasoline.

B.)<u><em>The advantage of attempting to remove the block effect is</em></u>

The completely randomized designs does not prove that H0 is incorrect only that it cannot be rejected.

Step-by-step explanation:

<em><u /></em>

<em><u>Using Two-way ANOVA method</u></em>

Given problem

<em><u>Observation              I          II       III          Row total (xr)</u></em>

A                              18 21 20            59

B                            24 26 27             77

C                            30 29 34             93

D                            22 25 24            71

<u>E                            20 23 24           63                      </u>

Col total (xc)             114 124 129        367

∑x²=9233→(A)

∑x²c/r

=1/5(114²+124²+129²)

=1/5(12996+15376+16641)

=1/5(45013)

=9002.6→(B)

∑x²r/c

=1/3(59²+77²+93²+71²+67²)

=1/3(3481+5929+8649+5041+4489)

=1/3(27589)

=9196.3333→(C)

(∑x)²/n

=(367)²/15

=134689/15

=8979.2667→(D)

Sum of squares total

SST=∑x²-(∑x)²/n

=(A)-(D)

=9233-8979.2667

=253.7333

Sum of squares between rows

SSR=∑x²r/c-(∑x)²/n

=(C)-(D)

=9196.3333-8979.2667

=217.0667

Sum of squares between columns

SSC=∑x²c/r-(∑x)²/n

=(B)-(D)

=9002.6-8979.2667

=23.3333

Sum of squares Error (residual)

SSE=SST-SSR-SSC

=253.7333-217.0667-23.3333

=13.3333

<u>ANOVA table</u>

Source                 Sums         Degrees      Mean Squares

of Variation       of Squares   of freedom

<u>                               SS                 DF              MS       F p-value</u>

B/ w     SSR=217.0667              4 MSR=54.2667    32.56 0.0001

rows

B/w     SSC=23.3333         c-1=2 MSC=11.6667        7 0.01

columns

<u>Error (residual)SSE=13.3333 (r-1)(c-1)=8 MSE=1.6667                  </u>

<u>Total SST=253.7333 rc-1=14                                                        </u>

Conclusion:

<u> 1. F for between Rows</u>

The critical region for F(4,8) at 0.05 level of significance=3.8379

The calculated F for Rows=32.56>3.8379

Therefore H0 is rejected

<u>2. F for between Columns</u>

The critical region for F(2,8) at 0.05 level of significance=4.459

We see that the calculated F for Colums=7>4.459

therefore H0 is rejected,and concluded that there is significant differentiating between columns

<u><em>Part B:</em></u>

To analyze the data for completely  randomized designs click on anova two factor without replication  in the data analysis dialog box of the excel spreadsheet.

The following table is obtained

Source DF             Sum                  Mean           F Statistic

<u>                 (df1,df2)    of Square (SS) Square (MS)                    P-value</u>

Factor A       1 1496.5444 1496.5444 769.6514          0.001297

Rows

Factor B -     2 19.4444           9.7222               5                  0.1667

Columns

Interaction

AB               2    3.8889   1.9444        0.1013         0.9045

<u> Error     12   230.4            19.2                                           </u>

<u>Total 17 1750.2778 102.9575                                                         </u>

<u />

<u>Factor - A- Rows</u>

Since p-value < α, H0 is rejected.

<u>Factor - B- Columns</u>

Since p-value > α, H0 can not be rejected.

The averages of all groups assume to be equal.

<u>Interaction AB</u>

Since p-value > α, H0 can not be rejected.

<u><em>The advantage of attempting to remove the block effect is</em></u>

The completely randomized designs does not prove that H0 is incorrect only that it cannot be rejected.

3 0
3 years ago
Suppose $1000 is invested at 8%, compounded quarterly. How much is in the account at the end of 4 years?
guajiro [1.7K]
The correct answer is $320
3 0
3 years ago
What is the domain and range of f(x)=2|x+2|-8
RideAnS [48]

Answer:

The domain of f(x) is {x : x ∈ R} and the range is {y : y ≥ -8}

Step-by-step explanation:

- The domain of the function is the values of x which make the

  function defined

- The rang is the corresponding values of y with the domain

- The parent function of f(x) is g(x) = IxI

- The graph of this function represented by 2 lines starting from  

  the origin, one of them with positive slope and the other with negative

  slope and both of them over the x-axis

- The Domain of g(x) is {x : x ∈ R} where R is the set of real numbers

- That mean the domain of g(x) is all real numbers

- The range of g(x) is {y : y ≥ 0}

- That mean the range is all real numbers greater than or equal to zero

- f(x) is the image of g(x) after some transformations

- g(x) multiplied by 2 that mean vertical stretch.

- Then x add by 2 that mean horizontal translation to the left by 2 units

- Then subtract 8 from it means vertical translation down by 8 units

- The figure of f(x) is the same lines but stretched vertically away from

   x-axis and moved to the left 2 units and down 8 units

- That means the image of the origin is (-2 , -8)

- So the domain does not change it is the all real numbers

- The domain of f(x) is {x : x ∈ R}

- But the range changes is because the graph of the function starts

 from -8 not from 0

- Then the range of f(x) is {y : y ≥ -8}

* The domain of f(x) is {x : x ∈ R} and the range is {y : y ≥ -8}

- <em>Look to the attached graph for more understand</em>

7 0
3 years ago
The table of values represents the function t(x) and the graph shows the function g(x).
IrinaK [193]

Answer:

  The maximum value of the table t(x) has a greater maximum value that the graph g(x)

Step-by-step explanation:

The table shows t(x) has two (2) x-intercepts: t(-3) = t(5) = 0. The graph shows g(x) has two (2) x-intercepts: g(1) = g(5) = 0. Neither function has fewer x-intercepts than the other.

The table shows the y-intercept of t(x) to be t(0) = 3. The graph shows the y-intercept of g(x) to be g(0) = -1. The y-intercepts are not the same, and that of t(x) is greater than that of g(x).

The table shows the maximum value of t(x) to be t(1) = 4. The graph shows the maximum value of g(x) to be g(3) = 2. Thus ...

  the maximum value of t(x) is greater than the maximum value of g(x)

8 0
3 years ago
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