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3 years ago

Which term describes body parts of different organisms that are similar in form?

Biology

1 answer:

Serggg [28]3 years ago

3 0

Answer:

A. homologous structures

Explanation:

The answer is homologous structures.

A male cat and a male dog both have masculine penile <em>structures. </em>

They are are two different organisms, but the two penises are in a similar form because they are both penises.

Same Structures = Homo Structures

Same with any other parts

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3 years ago

Read 2 more answers

assume that life on Mars requires cell potential to be 100mV, and the extracellular concentrations of the three major species ar

svetlana [45]

Answer:

Explanation:

From the information given:

The cell potential on mars E = + 100 mV

By using Goldman's equation:

$E_m = \dfrac{RT}{zF}In \Big (\dfrac{P_K[K^+]_{out}+P_{Na}[Na^+]_{out}+P_{Cl}[Cl^-]_{out} }{P_K[K^+]_{in}+P_{Na}[Na^+]_{in}+ P_{Cl}[Cl^-]_{in}} \Big )$

Let's take a look at the impermeable cell with respect to two species;

and the two species be Na⁺ and Cl⁻

$E_m = \dfrac{RT}{zF} In \dfrac{[K^+]_{out}}{[K^+]_{in}}$

where;

z = ionic charge on the species = + 1

F = faraday constant

∴

$100 \times 10^{-3} = \Big (\dfrac{8.314 \times 298}{1\times 96485} \Big) \mathtt{In} \Big ( \dfrac{4}{[K^+]_{in}} \Big)$

$100 \times 10^{-3} = 0.0257 \Big ( \dfrac{4}{[K^+]_{in}} \Big)$

$3.981= \mathtt{In} \Big ( \dfrac{4}{[K^+]_{in}} \Big)$

$exp ( 3.981) = \dfrac{4}{[K^+]_{in}} \\ \\ 53.57 = \dfrac{4}{[K^+]_{in}}$

$[K^+]_{in} = \dfrac{4}{53.57}$

$[K^+]_{in} = 0.0476$

For [Cl⁻]:

$100 \times 10^{-3} = -0.0257 \ \mathtt{In} \Big ( \dfrac{120}{[Cl^-]_{in}} \Big)$

$-3.981 = \ \mathtt{In} \Big ( \dfrac{120}{[Cl^-]_{in}} \Big)$

$0.01867 = \dfrac{120}{[Cl^-]_{in}}$

$[Cl^-]_{in} = \dfrac{120}{0.01867}$

$[Cl^-]_{in} =6427.4$

For [Na⁺]:

$100 \times 10^{-3} = 0.0257 \Big ( \dfrac{145}{[Na^+]_{in}} \Big)$

$53.57= \Big ( \dfrac{145}{[Na^+]_{in}} \Big)$

$[Na^+]_{in}= 2.70$

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3 years ago

These superior inherited traits led Darwin to another idea, the finches' increased

lesya [120]

Answer:

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3 years ago

The concentration of a biomolecule inside a rod-shaped prokaryotic cell is 0.0037 m. calculate the number of molecules inside th

Talja [164]

First, let calculate the volume of the rod shaped-bacteria:

S = length of the bacteria * surface of its side = 4.1 * (0.45 *0.45 * 3.14) = 2.6 µm3

Now, let's convert the moles into molecules (with Avogadro's law):

0.0037mol/L = 0.0037 * 6.023 *10^23 = 2.22 *10^21 molecules / L

Now let's convert The volume and the concetrnation into µm3 (molecules / µm3)

1 L = 1 dm3 = 1000 cm3 = 1000000 mm3 = 10^9 µm3

so 2.22 *10^21 molecules / L = 2.22 10^ 12 molecules / µm3

The answer is 2.22 10^ 12 molecules / µm3

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3 years ago

What is the male reproductive system cell

erastova [34]

Answer:

In the human reproductive process, two kinds of sex cells, or gametes (GAH-meetz), are involved. The male gamete, or sperm, and the female gamete, the egg or ovum, meet in the female's reproductive system.

Explanation

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3 years ago