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Viefleur [7K]
3 years ago
13

11 is 10% more than ?

Mathematics
2 answers:
djyliett [7]3 years ago
7 0

Answer: 21

Step-by-step explanation:

guapka [62]3 years ago
6 0

Answer:

21

Step-by-step explanation:

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How do I solve these questions?
PSYCHO15rus [73]

Function rule:  a = 20w + 115

Slope: 20

Initial value: 115

------------------------------------------

We start with $115 in the account. This is the initial value. Each week we add on $20.

So we add $20 for 1 week

We add 2*20 = $40 for 2 weeks

We add 3*20 = $60 for 3 weeks

etc etc

In general, we add 20*w dollars for w weeks onto 115 to get a = 20w+115

The slope is 20 because this is the rate of change, ie how fast the account grows. It grows 20 dollars per week.

4 0
3 years ago
PLS HELP ASP HURRY BEST ANSWER GETS BRAINLESST!​
faltersainse [42]

Answer:

i cant see your pic

Step-by-step explanation:

7 0
4 years ago
Read 2 more answers
Subtract 37/55-32/55
lana66690 [7]
The answer would be 5/55 because if you subtract 32 from 37 you would end up with 5 and because the denominator was the same you keep the denominator the same.
5 0
4 years ago
Inverse of g(x)=-x^5-3
Artyom0805 [142]

Answer:

<h2>{g}^{ - 1} (x) =  \sqrt[5]{ - x - 3}</h2>

Step-by-step explanation:

<h3>g(x) =  -  {x}^{5}  - 3</h3>

To find the inverse of g(x) equate g(x) to y

That's

<h3>y =  -  {x}^{5}  - 3</h3>

<u>Next interchange the terms</u>

x becomes y and y becomes x

We have

<h3>x =  -  {y}^{5}  - 3</h3>

<u>Next make y the subject</u>

Multiply both sides by - 1

That's

<h3>{y}^{5}  + 3 =  - x</h3>

Send 3 to the right side of the equation

That's

{y}^{5}  =  - x - 3

<u>Find the 5th root of both sides</u>

That's

<h3>\sqrt[5]{ {y}^{5} }  =  \sqrt[5]{ - x - 3}  \\ y =   \sqrt[5]{ - x - 3}</h3>

We have the final answer as

<h3>{g}^{ - 1} (x) =  \sqrt[5]{ - x - 3}</h3>

Hope this helps you

5 0
4 years ago
This is a variation acitivity:
sergey [27]

\bf \qquad \qquad \textit{direct proportional joint variation} \\\\ \textit{\underline{y} varies jointly with \underline{x} and \underline{z}}\qquad \qquad y=kxz\impliedby \begin{array}{llll} k=constant\ of\\ \qquad variation \end{array} \\\\[-0.35em] \rule{34em}{0.25pt}


\bf \stackrel{\textit{\underline{I} varies jointly with \underline{P} and \underline{t}}}{I=kPt} \\\\\\ \textit{we also know that } \begin{cases} P=2000\\ t=4\\ I=320 \end{cases}\implies 320=k(2000)(4)\implies \cfrac{320}{(2000)(4)} \\\\\\ 0.04=k\qquad therefore\qquad \boxed{I=0.04Pt} \\\\\\ \textit{if P=5000 and t=7, what is \underline{I}?}\qquad I=0.04(5000)(7)\implies I=1400

8 0
3 years ago
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