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Hoochie [10]
4 years ago
14

I need help doing this.

Mathematics
1 answer:
melisa1 [442]4 years ago
3 0

Answer:

6.63

Step-by-step explanation:

6.63324958071

the hundredth spot is the first 3, so you go to the second 3, because its under 5, the second 3 stays the same and doesn't round up to 4.

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a certain forest covers an area of 3100 km^2. suppose that each year this area decreases by 8.25%. what will the area be after 1
IrinaK [193]
A decrease of 8.25% means the reduction factor is 100-8.25=91.75%=0.9175.
The shrinkage over 15 years is 0.9175¹⁵=0.27485 approx, so the size of the forest will be 3100×0.27485=852 sq km approx.
8 0
3 years ago
In the number 0.222 the 2 next to the decimal point represents a value that is how many times as large as that represented by th
Ronch [10]

Answer:

100 times

Step-by-step explanation:

0.002 * 100 = 0.2

4 0
4 years ago
Consider the following equation. f(x, y) = y3/x, P(1, 2), u = 1 3 2i + 5 j (a) Find the gradient of f. ∇f(x, y) = Correct: Your
BaLLatris [955]

f(x,y)=\dfrac{y^3}x

a. The gradient is

\nabla f(x,y)=\dfrac{\partial f}{\partial x}\,\vec\imath+\dfrac{\partial f}{\partial y}\,\vec\jmath

\boxed{\nabla f(x,y)=-\dfrac{y^3}{x^2}\,\vec\imath+\dfrac{3y^2}x\,\vec\jmath}

b. The gradient at point P(1, 2) is

\boxed{\nabla f(1,2)=-8\,\vec\imath+12\,\vec\jmath}

c. The derivative of f at P in the direction of \vec u is

D_{\vec u}f(1,2)=\nabla f(1,2)\cdot\dfrac{\vec u}{\|\vec u\|}

It looks like

\vec u=\dfrac{13}2\,\vec\imath+5\,\vec\jmath

so that

\|\vec u\|=\sqrt{\left(\dfrac{13}2\right)^2+5^2}=\dfrac{\sqrt{269}}2

Then

D_{\vec u}f(1,2)=\dfrac{\left(-8\,\vec\imath+12\,\vec\jmath\right)\cdot\left(\frac{13}2\,\vec\imath+5\,\vec\jmath\right)}{\frac{\sqrt{269}}2}

\boxed{D_{\vec u}f(1,2)=\dfrac{16}{\sqrt{269}}}

7 0
3 years ago
Help please please help…….
olga nikolaevna [1]

Answer:

Choice A

Step-by-step explanation:

y-intercept = -3

double-checked on calculator

8 0
3 years ago
There are only one answer answer it fast in two minutes
Gemiola [76]

Answer:

first one i think Good luck

7 0
3 years ago
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