How many complex roots does the equation below have?
1 answer:
Answer:
The number of complex roots is 6.
Step-by-step explanation:
Descartes's rule of signs tells you that the number of positive real roots is 0. The number of negative real roots will be at most 2. The minimum value of the left side will be between x=0 and x=-1, but will never be negative. Thus all six roots are complex.
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The magnitude of x^3 will exceed the magnitude of x^6 only for values of x between -1 and 1. Since the magnitude of either of these terms will not be more than 1 in that range, the left-side expression must be positive everywhere.
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Let
x--------> the measure of the adjacent interior angle
y--------> the measure of an exterior angle at the vertex of a polygon
we know that
The measure of the adjacent interior angle and the measure of an exterior angle at the vertex of a polygon are supplementary angles
so
°
<u>Examples</u>
case 1)
<u>In a square</u>
°
so
°
In this case
The measure of an exterior angle at the vertex of a polygon equals the measure of the adjacent interior angle
case 2)
<u>an equilateral triangle</u>
°
so
°
In this case
The measure of an exterior angle at the vertex of a polygon is not equals the measure of the adjacent interior angle
therefore
<u>the answer is</u>
sometimes
Answer:
B
Step-by-step explanation:
GI is made up of the segments GH and HI. In other words:
We know that GH is 2 and GI is 7. Substitute:
Subtract 2 from both sides:
So, our answer is B.
And we're done!