3 years ago

8x10^4 is how many times as large as 4x10^-5

Mathematics

1 answer:

Tresset [83]3 years ago

7 0

Answer:

Dccr5-5#8-5#2##5#5#8##6

Step-by-step explanation:

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Varvara68 [4.7K]

Well the answer is 12-14=%58=x

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3 years ago

A rectangular pan has a length that is the width. The total area of the pan is 432 in.2. What is the width of the cake pan? A =

spayn [35]

Answer:

Let width = w

length = 4w/3

Area = 432 = length*width = w*4w/3

4w^2/3 = 432

w^2 = 432*3/4 = 324

w = 18

so the width of the cake pan is 18 inches.

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3 years ago

Which is one way to check 102÷6=17 A.105÷10=10.5 B.17÷6=102 C.100÷5=20 D.100×5=500

Andru [333]

Hello!

The correct answer choice should be B. but the sign should be a multiplication sign...

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3 years ago

Work out the area of a rectangle with base, b = 34mm and perimeter, P = 86mm.

Nana76 [90]

Answer:

306mm²

Step-by-step explanation:

the height h = 86/2 -34 = 43-34=9mm

the area = 34×9= 306mm²

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3 years ago

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A kite is being flown at a 45 angle. The string of the kite is 120 feet long. How high is the kite above the point at which the

MrRissso [65]

Answer: The height of the kite above the point at which the string is held is $120\sqrt{2}$ feet.

Step-by-step explanation:

Given : A kite is being flown at $45^{\circ}$ . The string of the kite is 120 feet long.

Let AB denote the string of kite and AC be the height of the kite above the point at which the string is held.

Now, in right Δ ABC

$\sin45^{\circ}=\frac{AC}{AB}\\\Rightarrow\ \frac{1}{\sqrt{2}}=\frac{AC}{120}\\\Rightarrow\ AC=120\sqrt{2}$

hence, The height of the kite above the point at which the string is held is $120\sqrt{2}$ feet.

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3 years ago

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