Sub x = 2-y^2 to Q, we get:
Q = 3(2-y^2)*y^2
let y^2 = k
Q = 3(2-k)k = 3(2k-k^2)
2k-k^2 has a max when k = 1
Then y^2 = 1 -> y = 1 or -1
The answer is 1,000 if you think about 30*1,000=30,000
Answer:
176/231
Step-by-step explanation:
88 blue marbles, 55 green marbles, and 88 red marbles =231 marbles
P (blue or red marble) = number of red or blue/ total
= 88+88 / 231
=176/231
Answer:
1.65 minutes
Step-by-step explanation:
10 9/10 + 5 3/5 = 16 1/2
16 1/2 divided by 20 = 1.65 or 33/20