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3 years ago

HOW CAN ARITHMETIC AND GEOMETRIC SEQUENCES BECOME LINEAR AND EXPONENTIAL FUNCTIONS?

1 answer:

vladimir1956 [14]3 years ago

3 0

A sequence is a set of numbers, called terms, arranged in some particular order. An arithmetic sequence is a sequence with the difference between two consecutive terms constant. The difference is called the common difference. A geometric sequence is a sequence with the ratio between two consecutive terms constant.

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Yanka [14]

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3 years ago

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A circle has its center at the center of a square with 12-inch sides. Using 3.14 for pi, find the area of the square not covered

Dmitrij [34]

So first, find the area of the square. 12x12= 144inches^2
Then find the area of the circle. To do this we use pi x r^2. The radius of the circle is 6 inches. Pi x 6^2 = 113.04inches^2.
144 - 113.04 = 30.6, so your answer is 30.6 inches^2

The circles circumference is worked out by using pi x d. The diameter is 12 inches, so 3.14x12 = 37.68 inches.
The squares perimeter is 12 x 4 = 48 inches.
If you round up the circumference of the circle to the nearest integer, you get 38 inches. The ratio would therefore be, 38:48, which can be rounded down to 19:24 :)

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3 years ago

Which words describe this shape? Choose all that apply. kite quadrilateral rhombus parallelogram Submit

NARA [144]

That's really hard I can't figure it out at all by any chance

8 0

3 years ago

Can anyone fill this out for me? show work too pls thanks

givi [52]

1) circumference= 3.14 x 12
C= 37.68

7 0

3 years ago

An insurance company sells automobile liability and collision insurance. Let X denote the percentage of liability policies that

qaws [65]

Answer:

-764.28

Step-by-step explanation:

Given the joint cumulative distribution of X and Y as

$F(x,y) = \frac{xy(x+y)}{2000000}\ \ \ \, \ 0\leq x100, 0\leq y\leq 100$

#First find $F_x$ and probability distribution function , $f_x(x)$ :

$F_x(x)=F(x,100)\\\\\\=\frac{100x(x+100)}{2000000}\\\\\\\\=\frac{100x^2+10000x}{2000000}\\\\\\=>f_x(x)=\frac{x}{10000}+\frac{1}{200}$

#Have determined the probability distribution unction , $f_x(x)$ , we calculate the Expectation of the random variable X:

$E(X)=\int\limits^{100}_0 \frac{x^2}{10000}+\frac{x}{200} dx \\\\\\\\=|\frac{x^3}{30000}+\frac{x^2}{400}|\limits^{100}_0\\\\=58.33\\\\$

#We then calculate $E(X^2)$ :

$E(X^2)=\int\limits^{100}_0 \frac{x^3}{10000}+\frac{x^2}{200}\ dx\\\\=\frac{x^4}{40000}+\frac{x^3}{600}|\limits^{100}_0=4166.67\\\\Var(X)=E(X^2)-(E(X))^2=4166.67-58.33^2\\\\Var(X)=764.28$

Hence, the Var(X) is 764.28

4 0

3 years ago