Meg wants to find hie nany phones the company activated in one minute explain why meg can use 15000 divided by 50 to
1 answer:
Answer:
300 phones the company activated in one minute
As per unitary method, calculation been done to find the value of single unit from the value of multiple units.
So, she is dividing the total number of phone activated by number of minutes taken to activate to find phone activate in one minute.
Step-by-step explanation:
Here is the correct question: Meg wants to find how many phones the company activated in one minute. Explain why meg can use 15000 divided by 50 to find the answer.
As per unitary method, calculation been done to find the value of single unit from the value of multiple units.
Therefore, in the above question Meg knew the number of total phone activated by company in 50 minutes, which is 15000.
Now, she want to find how many phones the company activates in one minute.
So, she is dividing the total number of phone activated by number of minutes taken to activate to find phone activate in one minute.
Phones the company activated in one minute=
∴ 300 phones the company activated in one minute.
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Answer:
p(on schedule) ≈ 0.7755
Step-by-step explanation:
A suitable probability calculator can show you this answer.
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The z-values corresponding to the build time limits are ...
z = (37.5 -45)/6.75 ≈ -1.1111
z = (54 -45)/6.75 ≈ 1.3333
You can look these up in a suitable CDF table and find the difference between the values you find. That will be about ...
0.90879 -0.13326 = 0.77553
The probability assembly will stay on schedule is about 78%.
