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Goshia [24]
3 years ago
10

Simplify the expression for 3 [(11-6)^2÷5]

Mathematics
2 answers:
Svetradugi [14.3K]3 years ago
6 0

the answer to your question is 15  

storchak [24]3 years ago
4 0

Answer:

<em>15</em>

Step-by-step explanation:

Use the correct order of operations.

3[(11-6)^2÷5] =

= 3[(5)^2÷5]

= 3[25÷5]

= 3[5]

= 15

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A mattress store in Stafford purchased a mattress at a cost of $255 and marked it up 100%. Later on, Cassie bought the mattress.
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Q1. For each of the following values of a,b and c, where
Rudik [331]

<u>Explanation</u><u>:</u><u>-</u>

<h3>⟨a⟩</h3>

Given that

a = -20

b = -10

c = 5

⟨i⟩ LHS = a÷b

⇛ -20÷-10

⇛ -20/-10

⇛ 2

and

RHS = b÷a

⇛ -10÷-20

⇛ -10/-20

⇛ 1/2

LHS ≠ RHS

a÷b ≠ b÷a

⟨ii⟩

LHS = (a÷b)÷c

⇛ (-20÷-10)÷5

⇛ 2÷5

⇛ 2/5

RHS = a÷(b÷c)

⇛ -20÷(-10÷5)

⇛ -20÷-2

⇛ -20/-2

⇛ 10

LHS ≠ RHS

(a÷b)÷c ≠ a÷(b÷c)

⟨iii⟩ LHS = a÷(b+c)

⇛ -20÷(-10+5)

⇛ -20÷(-5)

⇛ -20/-5

⇛ 4

RHS = (a÷b)+(a÷c)

⇛ (-20÷-10)+(-20÷5)

⇛ 2+(-4)

⇛ 2-4

⇛ -2

LHS ≠ RHS

a÷(b+c) ≠ (a÷b)+(a÷c)

<h3>⟨b⟩.</h3>

Given that

a = -40

b = 10

c = -5

⟨i⟩ LHS = a÷b

⇛ -40÷1

⇛ -40/1

⇛-40

and

RHS = b÷a

⇛ 10÷-40

⇛ 10/-40

⇛ -1/4

LHS ≠ RHS

a÷b ≠ b÷a

⟨ii⟩.

LHS = (a÷b)÷c

⇛ (-40÷10)÷-5

⇛ -4÷-5

⇛ 4/5

RHS = a÷(b÷c)

⇛ -40÷(10÷-5)

⇛ -40÷-2

⇛ -40/-2

⇛ 20

LHS ≠ RHS

(a÷b)÷c ≠ a÷(b÷c)

⟨iii⟩ LHS = a÷(b+c)

⇛ -40÷(10-5)

⇛ -40÷(5)

⇛ -40/5

⇛ -8

RHS = (a÷b)+(a÷c)

⇛ (-40÷10)+(-40÷-5)

⇛ (-4)+8

⇛ 8-4

⇛ 4

LHS ≠ RHS

a÷(b+c) ≠ (a÷b)+(a÷c)

<u>Conclusion :-</u>

  1. Commutative property
  2. Associative Property
  3. Distributive Property does not hold in the set of integers under Division
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sveticcg [70]

Answer:

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