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Ganezh [65]
3 years ago
12

Locate the element zinc (Zn) on the periodic table. How many protons does an atom of zinc contain? How many electrons does an at

om of zinc contain? How many neutrons does an atom of zinc contain? Give your answer to the nearest whole number.
Chemistry
2 answers:
Lady bird [3.3K]3 years ago
4 0
<h2>Answer:</h2><h3>Part 1:</h3>

Location the element zinc (Zn) on the periodic table:

  •    Group number : 12
  •     Period number : 4
  •     Block :  d block
  •      Element : Transition elements.
<h3>Part 2:</h3>

Protons in an atom of Zn:  30

<h3>Part 3:</h3>

Electrons in a Zn atom: 30

<h3>Part 4 :</h3>

Neutron in an atom of Zn: 35


<h3 />
Darya [45]3 years ago
4 0

<u>Answer:</u> Number of protons and electrons in Zinc are 30 and number of neutrons in zinc are 35.

<u>Explanation:</u>

Zinc is the 30th element of the periodic table having mass number of 65.

  • Atomic number is defined as the number of protons or number of electrons present in an element. It is represented as Z.

Atomic number = Number of protons = Number of electrons

For Zinc:

Z = 30

So, Number of protons = Number of electrons = 30

  • Mass number is defined as the sum of number of protons and number of neutrons. It is represented as A.

Mass number = Number of neutrons + Number of protons

A = 65

So, Number of neutrons = 65 - 30 = 35

Hence,  number of protons and electrons in Zinc are 30 and number of neutrons in zinc are 35.

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ki77a [65]

Answer:

6Br⁻ + XeO₃ + 6H⁺ → 3Br₂ + Xe + 3H₂O  

Explanation:

First, we need to write the half-reactions:

2Br⁻ → Br₂ + 2e⁻ Oxidation -Balanced yet-

XeO₃ →  Xe Reduction

To balance the reduction in acidic aqueous solution we need to add waters in the other side of the reaction as oxygens are present:

XeO₃ →  Xe + 3H₂O

And H⁺ as hydrogens from water we have:

XeO₃ + 6H⁺ →  Xe + 3H₂O

To balance the charge:

<h3>XeO₃ + 6H⁺ + 6e⁻ →  Xe + 3H₂O  Reduction -Balanced-</h3><h3 />

To cancel out the electrons of both half-reaction we need to multiply oxidation 3 times:

6Br⁻ → 3Br₂ + 6e⁻

XeO₃ + 6H⁺ + 6e⁻ →  Xe + 3H₂O  

And the balanced reaction in acidic aqueous solution is the sum of both half-reactions:

<h3>6Br⁻ + XeO₃ + 6H⁺ → 3Br₂ + Xe + 3H₂O  </h3>
5 0
3 years ago
A mixture of two compounds, A and B, was separated by extraction. After the compounds were dried, their masses were found to be:
Arlecino [84]

Answer:

The percent recovery from re crystallization for both compounds A and B is 69.745 and 81.44 % respectively.

Explanation:

Mass of compound A in a mixture  = 119 mg

Mass of compound A after re-crystallization = 83 mg

Percent recovery from re-crystallization :

\frac{\text{Mass after re-crystallization}}{\text{Mass before re-crystallization}}\times 100

Percent recovery of compound A:

\frac{83 mg}{119 mg}\times 100=69.74\%

Mass of compound B in a mixture  = 97 mg

Mass of compound B after re-crystallization = 79 mg

Percent recovery of compound B:

\frac{79 mg}{97 mg}\times 100=81.44\%

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Answer:Please find the attachment

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7 0
4 years ago
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You could use another word for change can be variable witch means change and if you times the one two more times then you would get four because two time two would be four and times the one would be four.


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