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Natasha2012 [34]
2 years ago
9

What is the empirical formula of propene CH3 CH2 CH2​

Chemistry
1 answer:
kiruha [24]2 years ago
6 0

Answer:

<u>CH</u>

Explanation:

Molecular formula of propene : <u>C₃H₆</u>

Take the HCF of carbon and hydrogen atoms :

  • 3 = 3
  • 6 = 2 x 3

Then, we can write the formula as :

  • 3CH
  • This means there are 3 moles present

Empirical Formula :

  • Molecular Formula / No. of moles
  • C₃H₆ / 3
  • <u>CH</u>

<u></u>

The empirical formula of propene is <u>CH</u>

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Calculate the net change in enthalpy for the formation of one mole of acrylic acid from calcium carbide, water and carbon dioxid
kiruha [24]

Answer:

-471 Kj/mole acrylic acid

Explanation:

THIS IS THE COMPLETE QUESTION BELOW;

There are two steps in the usual industrial preparation of acrylic acid, the immediate precursor of several useful plastics. In the first step, calcium carbide and water react to form acetylene and calcium hydroxide: CaC (s) + 2 H2O(g) - CH (9) + Ca(OH),(s) AH -414. kJ In the second step, acetylene, carbon dioxide and water react to form acrylic acid: 6 C H (9) + 3 CO2(9) + 4H2O(g) - SCH,CHCO,H) AH-132. kJ Calculate the net change in enthalpy for the formation of one mole of acrylic acid from calcium carbide, water and carbon dioxide from these reactions. Round your answer to the nearest kJ. x 5 ?

The two equations from the reaction can be written as;

a)CaC₂(s) + 2H₂O(l) ------->C₂H₂(g) + CaOH₂(s)

Δ H= -414Kj ........................ equation (a)

b)6C₂H₂(g) +3CO₂(g)+4H₂O(g) -------> 5CH₂CHCO₂H(g) Δ H= 132Kj ...................... equation (b)

In equation (b)acrylic acid was produced by the reaction between Acetylene carbon dioxide and water

Then we can multiply equation(a) by factor of 6 and the ΔH Then we have (6× -414Kj)= ΔH= -2484Kj.

6CaC₂(s) + 12H₂O(l) ------->6C₂H₂(g) + 6CaOH₂(s)

Δ H= -2484Kj.................. equation (c)

6C₂H₂(g) +3CO₂(g)+4H₂O(g) -------> 5CH₂CHCO₂H(g) Δ H= 132Kj

Then add equation (c) and equation(b) then we have

6CaC₂(s) + 16H₂O(l)+3CO₂(g)------> 5CH₂CHCO₂H(g) + 6CaOH₂(s) ΔH= -2352Kj

ΔH(net)= -2352Kj/5moles

=-471Kj/mole

therefore, net change in enthalpy for the formation of one mole of acrylic acid from calcium carbide, water and carbon dioxide from these reactions. Round your answer to the nearest kJ. x 5 ? is -471Kj/mole acrylic acid

6 0
3 years ago
___CH4 + ___O2 → ___CO2 + ___H2O When you burn natural gas in the laboratory, methane burns. What numbers fill in the blanks to
Hitman42 [59]

Answer:

The coefficient are 1,2,1,2 ( option B is correct)

Explanation:

Step 1: Data given

Methane = CH4

Burning methane = CH4 + O2

Step 2: The unbalanced equation

CH4(g) + O2(g) → CO2(g) + H2O(g)

Step 3: Balancing the equation

CH4(g) + O2(g) → CO2(g) + H2O(g)

On the left side we have 4x H (in CH4), on the right side we have 2x H (in H2O). To balance the amount of H, on both sides, we have to multiply H2O (on the right side by 2).

CH4(g) + O2(g) → CO2(g) + 2H2O(g)

On the left side we have 2x O (in O2), on the right side we have 4x O (2x in CO2 and 2x in 2H2O). To balance the amount of O on both sides, we have to multiply O2 (on the left side by 2).

CH4(g) + 2O2(g) → CO2(g) + 2H2O(g)

The coefficient are 1,2,1,2 ( option B is correct)

3 0
3 years ago
Please help me, im studying for finals and i need an answer to this question! Will mark brainliest for the answers that are the
alex41 [277]

Answer:

group of people assembled for religious worship.

a second definition:

a gathering or collection of people, animals, or things.

other words that mean the same thing as cogeneration:

assembly gathering assemblage convocation crowd flock group mass multitude!

I just need one more brainlest so if this helped! <3

5 0
3 years ago
Question 1 of 32
Svet_ta [14]

Answer:

[Ar] 3d¹⁰ 4s² 4p³

Explanation:

As = [Ar] 3d¹⁰ 4s² 4p³

5 0
3 years ago
Draw the structure of ozone according to VSEPR theory. What would be its associated molecular geometry?
vodka [1.7K]

Answer: Ozone's molecular geometry can be described as bent.

Explanation:

The molecular geometry of the O3 groups has a trigonal planar arrangement.

Here is a quick explanation of the molecular geometry of O3 including a quick description of the O3 bond angles.

Examining the  Lewis structure of  O3 we can see that there are a pair of unbounded valence electrons at the top of the structure.

Based on VSEPR Theory (Valence Shell Electron Pair Repulsion Theory) these electrons will repel the electron clouds of the two oxygen atoms on the end.

As a result they will be pushed down giving the 03 molecule a bent molecular geometry or shape.

The 03 bond angle will be 116° degrees since it has a Bent molecular geometry

8 0
3 years ago
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