Main sequence starts maybe
Answer:

Explanation:
Hello,
In this case, given the 0.0990 moles of the salt are soluble in 1.00 L of water only, we can infer that the molar solubility is 0.099 M. Next, since the dissociation of the salt is:

The concentrations of the A and B ions in the solution are:
![[A]=0.099 \frac{molAB_3}{L}*\frac{1molA}{1molAB_3} =0.0099M](https://tex.z-dn.net/?f=%5BA%5D%3D0.099%20%5Cfrac%7BmolAB_3%7D%7BL%7D%2A%5Cfrac%7B1molA%7D%7B1molAB_3%7D%20%20%3D0.0099M)
![[B]=0.099 \frac{molAB_3}{L}*\frac{3molB}{1molAB_3} =0.000.297M](https://tex.z-dn.net/?f=%5BB%5D%3D0.099%20%5Cfrac%7BmolAB_3%7D%7BL%7D%2A%5Cfrac%7B3molB%7D%7B1molAB_3%7D%20%20%3D0.000.297M)
Then, as the solubility product is defined as:
![Ksp=[A][B]^3](https://tex.z-dn.net/?f=Ksp%3D%5BA%5D%5BB%5D%5E3)
Due to the given dissociation, it turns out:
![Ksp=[0.099M][0.297M]^3\\\\Ksp=2.59x10^{-3}](https://tex.z-dn.net/?f=Ksp%3D%5B0.099M%5D%5B0.297M%5D%5E3%5C%5C%5C%5CKsp%3D2.59x10%5E%7B-3%7D)
Regards.
The mass of the empty flask is 17.4916 g. Now after feeling the ordinary water the mass of the flask is 43.9616 g. Thus the change of weight due to addition of ordinary water is (43.9616 - 17.4916) = 26.47 g.
Now as the density of the ordinary water at 20°C is 0.9982 g/ml, so 26.47 g is equivalent to
mL of water. Thus the capacity of the flask is 26.5177 mL.
Now the density of heavy water is 1.1053 g/mL at 20°C. Thus 26.5177 mL of heavy water is equivalent to (1.1053×26.5177) = 29.310 g.
Thus the total weight of the flask filled with heavy water will be (17.4916 + 29.310) = 46.8016 g at 20°C.
Option No. 1 at the cathode in both an electrolytic cell and a voltaic cell
Negative ion arrives at the anode, attracted by electrostatic forces, where they lose electrons. Loss of electrons is defined as oxidation.
The reverse process occur at the negative electrode, where positive ions pick up electrons. They are reduced.